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Viktor [21]
2 years ago
6

Calculate the ratio of H+ ions to OH– ions at a pH = 6. Find the concentration of H+ ions to OH– ions listed in Table B of your

Student Guide. Then divide the H+ concentration by the OH– concentration. Record this calculated ratio in Table A of your Student Guide.
Compare your approximated and calculated ratios of H+ ions to OH– ions at a pH = 6. Are they the same? Why or why not? Record your explanation in Table A.
What is the concentration of H+ ions at a pH = 6?
What is the concentration of OH– ions at a pH = 6?
What is the ratio of H+ ions to OH– ions at a pH = 6?
Chemistry
1 answer:
ipn [44]2 years ago
4 0

Answer:

The concentration of H+ ions at a pH of 6 is 0.000001. FIVE ZEROS AFTER THE DECIMAL

The concentration of OH- ions at a pH of 6 is 0.00000001. SEVEN ZEROS AFTER THE DECIMAL

The ratio of H+ ions to OH- ions at a pH of 6 is 100:1

Explanation:

For the concentrations of the H+ ions and OH- ions look at your chart on the student guide, it should be table B. But make sure to count the zeros right.

For the ratio it is easy, take the concentration of O+ ions and divide it by the concentration of the OH-. I recommend using desmos scientific calculator and just copying and pasting it into there. Good luck on your course!

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kotegsom [21]

Answer:

Atorvastatin has two chiral centers. The question doesn't include the box where have to answer but I can show you in an image where are located and their configuration.

Explanation:

The first image shows the chemical structure of atorvastatin and their chiral centers identified as 1 and 2 respectively.

The second image shows the Fischer projections corresponding to every chiral carbon 1 and 2. I wrote R so suggest that there are more carbon atoms forward but not only corresponds to carbon atoms.

You can see that the chiral carbon 1 has R configuration due to the direction from the main substituent to the second follow the clockwise.

The chiral carbon 2 has S configuration due to the direction from the main substituent to the second one go anticlockwise.

4 0
2 years ago
In which orbitals would the valence electrons for carbon <br> c. be placed?
katrin2010 [14]

Answer: 2s and 2p

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8 0
2 years ago
Read 2 more answers
A. The measured pH of a 0.100 M HCl solution at 25 degrees Celsius is 1.092. From this information, calculate the activity coeff
ra1l [238]

Answer:

activity coefficient \mathbf{\gamma =0.809}

activity coefficient \mathbf{\gamma = 0.791}

The change in pH in part A = 0.092

The change in pH in part B =  0.102

Explanation:

From the given information:

pH of HCl solution = 1.092

Activity of the pH solution [a] = 10^{-1.092}

[a] = 0.0809 M

Recall that [a] = \gamma × C

where;

\gamma  = activity coefficient

C = concentration

Making the activity coefficient the subject of the formula, we have:

\gamma = \dfrac{[a]}{C}

\gamma = \dfrac{0.0809 \ M}{0.100  \ M}

\mathbf{\gamma =0.809}

B.

The pH of a solution of HCl and KCl = 2.102

[a] = 10^{-2.102}

[a] = 0.00791 M

activity coefficient \gamma = \dfrac{0.00791 \ M}{0.01 \ M}

\mathbf{\gamma = 0.791}

C. The change in pH in part A = 1.091 - 1.0 = 0.092

The change in pH in part B = 2.102 -2.00 = 0.102

3 0
2 years ago
There are two types of nucleic acids, dna and rna. nearly all organisms use dna, not rna, as the central repository for genetic
Leya [2.2K]
Found the choices. Pls see attachment. 

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6 0
2 years ago
What is the value of Keq for the reaction expressed in scientific notation? 2.1 x 10-2 2.1 x 102 1.2 x 103 1.2 x 10-3
Lady_Fox [76]

Complete question:

Consider the reaction.

At equilibrium at 600 K, the concentrations are as follows.

2HF -----> H₂ + F₂

[HF] = 5.82 x 10-2 M

[H2] = 8.4 x 10-3 M

[F2] = 8.4 x 10-3 M

What is the value of Keq for the reaction expressed in scientific notation?

2.1 x 10-2

2.1 x 102

1.2 x 103

1.2 x 10-3

Answer:

2.1 × 10^-2

Explanation:

Kequilibrum(Keq) = product/reactant

Equation for the reaction :

2HF -----> H₂ + F₂

Therefore,

Keq = [H2][F2] / [HF]^2

Keq = [8.4 x 10-3][8.4 x 10-3] / [5.82 x 10-2]^2

Keq = [70.56 × 10^(-3 + - 3)]/[33.8724 × 10^(-2×2)]

Keq = [70.56 × 10^-6] / [33.8724 × 10^-4]

Keq = 2.0665 × 10^(-6 - (-4))

Keq = 2.0665 × 10^(-6 + 4)

Keq = 2.1 × 10^-2

7 0
2 years ago
Read 2 more answers
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