I think the best answer is D. Initialize the loop control variable prior to entering the loop body.
Please correct me if I'm wrong!! I'd be happy to fix it!! :)
Answer:
I am writing the Python program. Let me know if you want the program in some other programming language. Here is the Python code:
class Student(object):
def __init__(a,score=10):
a.score=score
def add_score(a,score):
a.score += 10
return (score)
def decrease_score(a,score):
a.score -=10
return (score)
def __str__(a):
current_score="{}".format(a.score)
return current_score
Explanation:
The program has a Student() class with attribute score.
It has the following methods:
__init__(): This method works as a constructor and enables to initialize score attribute of Student class. The value of score is initialized to 10. I have used a as the instance of Student class. However self keyword can also be used as an instance of the object to access the attributes and methods of Student class.
add_score() This method is used to add 10 to the score.
decrease_score() This method is used to decrease the score by 10.
__str__() This method is used to return the current score. format() is used here to return a string. current_score holds the value of the current score.
If you want the check the working of the program, then you can use the following statements to see the results on the output screen:
p = Student()
print(p)
p.add_score(p)
print(p)
This will create an object p of Student class and calls the above methods to display the values of the score according to the methods.
The program along with its output is attached.
Answer:
The code to this question can be given as:
Code:
int i,j,count_previous=0,count_next=0; //define variable
for (j=0; j<n; j++) //loop for array
{
if (x[0]==x[j]) //check condition
{
count_previous++; //increment value by 1.
}
}
for (i=0; i<n; i++) //loop
{
for (j=0; j<n; j++)
{
if (x[i]==x[j]) //check condition
{
count_next++; //increment value by 1.
}
}
if (count_previous>count_next) //check condition
{
mode=x[i-1];
}
else
{
mode=x[i];
count_previous=count_next; //change value.
count_next= 0 ; //assign value.
}
}
Explanation:
In the question it is define that x is array of the string elements that is already define in the question so the code for perform operation in the array is given above. In the code firstly we define the variable that is i, j, count_previous, count_next. The variable i,j is used in the loop and variable count_previous and count_next we assign value 0 that is used for check the values of array. Then we define the for loop in this loop we use conditional statement in the if block we check that array of zero element is equal to array of j value then the count_previous is increase by 1. Then we use nested loop It is also known as loop in a loop. In this first loop is used for array and the second loop is used for check array element.In this we use the condition that if array x of i value is equal to array x of j then count_next will increment by 1.Then we use another condition that is if count_previous is greater then count_next then mode of x is decrement by 1. else mode equal to array and count_previous holds the value of count_next and count_next is equal to 0.
Answer:
Python code explained below
Explanation:
f = open(input())
#loading the file, which will serve as the input
s1 = input()
s2 = input()
lines = f.readlines()
for line in lines:
line = line.strip(
# strip() removes characters from both left and right
if s1 <= line <= s2: #setting the range
print(line)
f.close()
#closing the file
They are probably looking for B. subscribing to journals is a good way of keeping up with what's happening in any field.
Of course, a very carefully curated professional network online is great for this too (but they said "personal" so that's not the answer)
Employers generally prefer that employees WORK as often as possible, so even though JUDICIOUS use of social media is a great way to keep current, D isn't the answer either.
Blogging about personal experiences is not necessarily going to teach you anything about work, though blogging professionally can be useful in gathering response from your readership
