Convection in the <u>Mantle</u> helps move pieces of the lithosphere around.
Answer:
mBCD = 28°
Step-by-step explanation:
The angle mBFD inscribes the arc mBD, so we have that:
mBFD = mBD/2
76 = mBD/2
mBD = 152°
The angle mBOD is a central angle related to the arc mBD, so we have that:
mBOD = mBD = 152°
In the quadrilateral BODC, the sum of internal angles needs to be equal to 360° (property of all convex quadrilaterals). The angles mCBO and mCDO are right angles, because EDC and ABC are tangents to the circle.
So, we have that:
mBOD + mCDO + mBCD + mCBO = 360
152 + 90 + mBCD + 90 = 360
mBCD = 360 - 90 - 90 - 152
mBCD = 28°
Answer: The answer is (D) Reflection across the line y = -x.
Step-by-step explanation: In figure given in the question, we can see two triangles, ΔABC and ΔA'B'C' where the second triangle is the result of transformation from the first one.
(A) If we rotate ΔABC 180° counterclockwise about the origin, then the image will coincide with ΔA'B'C'. So, this transformation can take place here.
(B) If we reflect ΔABC across the origin, then also the image will coincide with ΔA'B'C' and so this transformation can also take place.
(C) If we rotate ΔABC through 180° clockwise about the origin, the we will see the image will be same as ΔA'B'C'. Hence, this transformation can also take place.
(D) Finally, if we reflect ΔABC across the line y = -x, the the image formed will be different from ΔA'B'C', in fact, it is ΔA'D'E', as shown in the attached figure. So, this transformation can not take place here.
Thus, the correct option is (D).
If you would like to estimate 1/5 percent of 201, you can calculate this using the following steps:
1/5 percent of 201 = 1/5% of 201 = 1/5% * 201 = 1/5 / 100 * 201 = 1/500 * 201 = 201/500 = 0.402
Result: 1/5 percent of 201 is 0.402.