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2 years ago

8

Chris won at most 300 tickets at an arcade game. He spent 128 tickets on a ball and the rest on gum. Each piece of gum was 25 ti

ckets. Which inequality can be used to determine the greatest number of pieces of gum Chris could have purchased?

1 answer:

DENIUS [597]2 years ago

3 0

Answer:

The answer is about 7 pieces of gum

Step-by-step explanation:

because yes

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What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

astraxan [27]

ANSWER

The value of the expression is
$- 1$

EXPLANATION

Method 1: Rewrite as product of
${i}^{2}$

The expression given to us is,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4}$

We use the fact that
${i}^{2} = - 1$
to simplify the above expression.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

This implies,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times - 1 \times - 1 \times - 1\times - 1 \times - 1$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times 1 \times 1 \times - 1 = - 1$

Method 2: Use indices to solve.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0 + 1 + 2 + 3 + 4}$

This implies that,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{10}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( {{i}^{2}} )^{5}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( - 1 )^{5} = - 1$

8 0

2 years ago

Read 2 more answers

A cell phone tower at point A receives a cell phone signal from the southeast. A cell phone tower at point B receives a signal f

never [62]

Answer: Postulate 1: -4,-4

Postulate 2: D. The postulates guarantee that unique lines can be draw that they will meet at a unique point.

Step-by-step explanation:

7 0

1 year ago

What is the probability that a daughter of this mating will be a hemophiliac? Express your answer as a fraction using the slash

schepotkina [342]

Answer:

zero (0)

Step-by-step explanation:

probability of being hemophiliac and daughter is zero because females have 50% chance of being carrier.

where as males have 50% chance of being affected with hemophilia.

example for understanding: if after mating a girl have X chromosomes with hemophilia gene than she might have hemophilia but that is in rear case so probability is zero.

hope you understand my answer, thank you.

4 0

1 year ago

Find the output, yyy, when the input, xxx, is 555.<br><br> y = 5x-3y=5x−3

makkiz [27]

The output y is $y=22$

Explanation:

The expression is $y=5 x-3$

We need to determine the output y, when the value of input is x is 5.

That is, substituting $x=5$ in $y=5 x-3$ , we get,

$y=5(5)-3$

Multiplying the value within the bracket, we have,

$y=25-3$

Subtracting the terms, we get,

$y=22$

Thus, the value of output y is $y=22$

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1 year ago

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SAT Writing scores are normally distributed with a mean of 491 and a standard deviation of 113.A university plans to send letter

Sholpan [36]

Answer:

$z=1.405$

And if we solve for a we got

$a=491 +1.405*113=649.765$

So the value of height that separates the bottom 92% of data from the top 8% is 649.765.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(491,113)$

Where $\mu=491$ and $\sigma=113$

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.08$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.92 of the area on the left and 0.08 of the area on the right it's z=1.405. On this case P(Z<1.405)=0.92 and P(z>0.92)=0.08

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=1.405$

And if we solve for a we got

$a=491 +1.405*113=649.765$

So the value of height that separates the bottom 92% of data from the top 8% is 649.765.

6 0

1 year ago