Answer:
Pool 1 will be drained out just over a minute before pool 2.
Step-by-step explanation:
Pool 1
3700/31 = 119.35minutes
Pool 2
4228/42 = 100.67minutes
Pool 1 will be drained out just over a minute before pool 2
X=7/4+7/4y ,y∈ (One symbol I can't find but that's what I got)
The complete problem wants to know the more cost-effective choice is the printing company replaces its press machine every four years.
With this in mind, if they choose Company A, the total amount that needs to be paid to cover 12(4) = 48 months will be
Company A = 9 500 + 48(750) = $13 100
As for Company B, the highest probability of not having any repairs over the four years is 0.32 while there's 0.14 chance that number of repairs will be 3 over the time the contract is applied.
This means that the possible amounts to be paid to Company B are
Company B = 10 500 + 0(150) = $10 500
Company B = 10 500 + 1(150) = $10 650
Company B = 10 500 + 2(150) = $10 800
Company B = 10 500 + 3(150) = $10 950
This shows that choosing the machine from Company B would be better.
Hence, the answer is Company B<span>.</span>
Tension seems the obvious answer here, but then we are left with x. Since the horisontal line on a graph is 'x'. The answer appears to be Tension X (Tension on X axis. Hope this helps.
$34.60 rounds to $35
$24.99 rounds to $25
$527.85 rounds to $528
Now add the rounded numbers together:
$35
$25
$528
————-
$588.00 (estimated monthly expenses)
