Draw the electric field lines between a proton and an electron. According to Coulomb's law, how would the electrical force betwe
en these particles change if the product of their electrical charge increased?
1 answer:
Explanation:
An electron has a negative charge and a proton is a positively charged particle. Electric field lines are used to express the direction of the electric field. For a positive charge, it is outwards while for a negative charge it is inwards. The attached figure shows the electric field lines between a proton and an electron. The field lines emerge from proton and terminate at electron.
The electrical force between charges is given by :
r is the distance between charges
The force is directly proportional to the product of charges. It means that if the product of electrical charge increased, it means that the electrical force will increase proportionally.
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Answer:
Mass percent of nitrogen in the compound is 13,3%
Explanation:
Dumas method is an analytical method to determine nitrogen content in samples, thus:
CₐHₓNₙ + (2a+x/2) CuO → aCO₂ + ˣ/₂ H₂O + ⁿ/₂ N₂ + (2a+x/2) Cu
As the CO₂ is removed with KOH, in the mixture you have H₂O and N₂
At 25°C. the vapor pressure of water is 23,8 torr, that means that the pressure due to N₂ is:
726torr - 23,8torr = 702,2 torr.
Using gas law:
n = PV/RT
Where:
P is pressure (702,2torr≡ 0,924 atm)
V is volume (0,0318L)
R is gas constant (0,082atmL/molK)
And T is temperature (25°C≡298,15K)
Replacing, number of moles of N₂, n, are:
n = 1,20x10⁻³moles of N₂. In grams:
1,20x10⁻³moles of N₂× =<em> 0,0336 g of N₂</em>.
Thus, mass percent of nitrogen in the compound is:
×100= <em>13,3%</em>
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I hope it helps!