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hammer [34]
2 years ago
5

In [cu(nh3)4]co3, how many 3d electrons does copper have?

Chemistry
1 answer:
Andreyy892 years ago
4 0

Copper has a total of 29 electrons which would place the atom on the 29th number in the periodic table. In [Cu(NH₃)₄], there are 9 3d electrons of copper. The electron configuration of copper is [Ar] 4s² 3d¹⁰ but since there is a sub shell of its figuration that indicates only 1 electron filled, and since it is in the law that an electron must be paired up with another electron no matter how completely filled is the last sub shell, that is why the ast electron was given up to the other sub shell making it 9. The d shell can occupy around 10 electrons so it means that copper is a stable atom in the 3d sub shell. When you add [Cr(H₂O)₆]³⁺ (aq) and NH₃ (aq) a green solution because both are aqueous in form, you will get a purple solution containing [Cr(NH₃)₆]³⁺ (aq) and H₂O (l). 

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Explain how interactions between Earth’s spheres keep water cycling between them
Elenna [48]
There are several process in the nature, which keeps water cycling between them. By Precipitation, Earth's sphere gets water which we use in several ways, and by evaporation & sublimation, it goes back to upper spheres of the Earth's atmosphere and cycle happens again & again.

Hope this helps!
3 0
2 years ago
A student titrates 10.00 milliliters of hydrochloric acid of unknown molarity with 1.000 m naoh. it takes 21.17 milliliters of b
Dima020 [189]
Mole ratio for the reaction is 1:1
no of moles in NaOH that reacted= 1*21.17/1000=0.02117mols
 molarity of HCl=0.02117*10/1000
                         =2.117M
4 0
2 years ago
34.62 mL of 0.1510 M NaOH was needed to neutralize 50.0 mL of an H2SO4 solution. What is the concentration of the original sulfu
Igoryamba

0.1045M is the concentration of the original sulfuric acid solution

Explanation:

Titration is done to know the volume or concentration of unknown electrolyte.

Data given:

volume of acid = 50 ml

molarity of acid =?

volume of base NaOH = 34.62 ml

molarity of the base = 0.1510

For titration the formula used is,

Macid x Vacid = Mbase  x V base

Putting the values in above equation:

M acid x 50 = 34.62 x 0.1510

Macid = \frac{5.22762}{50}

           = 0.1045 M is the molarity of sulphuric acid solution used in neutralization of 0.1510 M base solution.

5 0
2 years ago
What is the limiting reactant for the reaction below given that you start with 10.0 grams of Al (molar mass 26.98 g mol-1) and 1
mezya [45]

Answer:

Al

Explanation:

4 Al  +  3 O₂  →  2 Al₂O₃

You need to figure out which one has the smaller mole ratio.  Convert both substances from grams to moles.

(10.0 g Al)/(26.98 g/mol) = 0.3706 mol Al

(19.0 g O₂)/(32.00 g/mol) = 0.5938 mol O₂

Now, use the mole ratios of reactant to product to see which substance produces the least amount of product.

(0.3706 mol Al) × (2 mol Al₂O₃/4 mol Al) = 0.1853 mol Al₂O₃

(0.5938 mol O₂) × (2 mol Al₂O₃/3 mol O₂) = 0.3958 mol Al₂O₃

Since aluminum produces the least amount of product, this is the limiting reagent.

4 0
2 years ago
A sample of H2SO4 contains 2.02 g of hydrogen, 32.07 g of sulfur, and 64.00 g of oxygen. How many grams of sulfur and grams of o
Gemiola [76]
From the chemical formula of sulfuric acid, we can see the molar ratio:

H : S : O 
2 : 1 : 4

Now, we convert the mass of hydrogen given into the moles of hydrogen. This is done using

Moles = mass / Mr
Moles = 7.27 / 1
Moles = 7.27

Therefore, the moles will be:

S = 7.27 / 2 = 3.64 moles
O = 7.27 * 2 = 14.54 moles

Now, the respective masses are:
S = 32 * 3.64 = 116.48 grams
O = 16 * 14.54 = 232.64 grams 
7 0
2 years ago
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