Molly bought a flat. At the beginning of

The cafeteria director at Great Minds School wants to know what percent of the students would choose vegetarian entrees if they

Korvikt [17]

Answer:

Sort a list of the students into a random order, then ask the first 353535 students on the list.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The annual interest rate of Marta's savings account is 7.2% in a simple interest is calculated quarterly. What is the periodic i

kkurt [141]

1. You have the following information:

-The annual interest rate is 7.2%.
- The simple interest is calculated quarterly.

2. Then, to solve this exercise and calculate the periodic interest rate of Marta's Account, you only have to divide the annual interest rate (7.2%) by 1/4 year. So, you have:

=(7.2%)(1/4)
=(7.2%)/4
=1.8%

What is the periodic interest rate of Marta's Account?

The answer is: 1.8%

7 0

2 years ago

The total operating costs of a monorail are paid using a combination of passenger fares and tax revenue. The farebox recovery ra

Vadim26 [7]

Answer:

0.57 or 0.56

Step-by-step explanation:

passenger fares + tax revenue = operating costs

Thus:

passenger fares = operating costs - tax revenue

= $69 million - $30 million

= $39 million

The ratio of passenger fares to total operating costs is:

$39 million

= 0.5652.

$69 million

To the nearest hundredth, the farebox recovery ratio is 0.57.

4 0

1 year ago

Is rap music more popular among young Indians than among young Asians? A sample survey compared 634 randomly chosen Indians aged

BabaBlast [244]

Answer:

Step-by-step explanation:

Confidence interval for the difference in the two proportions is written as

Difference in sample proportions ± margin of error

Sample proportion, p = x/n

Where x = number of successes

n = number of samples

For the indians,

x = 368

n1 = 634

p1 = 368/634 = 0.58

For the asians

x = 130

n2 = 567

p2 = 130/567 = 0.23

Margin of error = z√[p1(1 - p1)/n1 + p2(1 - p2)/n2]

To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025

This is the area in each tail. Since we want the area in the middle, it becomes

1 - 0.025 = 0.975

The z score corresponding to the area on the z table is 1.96. Thus, confidence level of 95% is 1.96

Margin of error = 1.96 × √[0.58(1 - 0.58)/634 + 0.23(1 - 0.23)/567]

= 1.96 × √0.00038422713 + 0.00031234568)

= 0.052

Confidence interval = 0.58 - 0.23 ± 0.052

Confidence interval = 0.35 ± 0.052

8 0

2 years ago

The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second. Use the central limi

Mila [183]

Answer:

0.048 is the probability that more than 950 message arrive in one minute.

Step-by-step explanation:

We are given the following information in the question:

The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.

Let X be the number of messages arriving at a multiplexer.

Mean = 15

For poison distribution,

Mean = Variance = 15

$\text{Standard Deviation} = \sqrt{\text{Variance}} = \sqrt{15} = 3.872$

From central limit theorem, we have:

$z = \displaystyle\frac{x-n\mu}{\sigma\sqrt{n}}$

where n is the sample size.

Here, n = 1 minute = 60 seconds

P(x > 950)

$P( x > 950) = P( z > \displaystyle\frac{950 - (60)(15)}{\sqrt{(15)(60)}}) = P(z > 1.667)$

$= 1 - P(z \leq 1.667)$

Calculation the value from standard normal z table, we have,

$P(x > 950) = 1 - 0.952 = 0.048$

0.048 is the probability that more than 950 message arrive in one minute.

3 0

2 years ago