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Yuliya22 [10]
1 year ago
11

Horizontal and parallel lines c and d are cut by transversal p. At the intersection of lines c and p, the uppercase left angle i

s angle 1 and the uppercase right angle is angle 2. At the intersection of lines d and p, the uppercase right angle is angle 3 and the bottom left angle is angle 4.
Which set of equations is enough information to prove that lines c and d are parallel lines cut by transversal p?

m∠1 = 81° and m∠2 = 99°
m∠3 = 99° and m∠4 = 99°
m∠2 = 99° and m∠4 = 99°
m∠4 = 81° and m∠1 = 81°
Mathematics
1 answer:
konstantin123 [22]1 year ago
5 0

Answer:

the answer is the option C

m∠2 = 99° and m∠4 = 99°

Step-by-step explanation:

edg 2020

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Solve for n the first can be like:-NP<40+70. -NP<110 the second one can be like : 4w-7k =28. solve for k and then, -7k=28-4w divide both sides by -7 that equal to k =-4-4w
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Mean of 7.2,8.5,7.0,8.1,6.7
klemol [59]

Answer:

7.5

Step-by-step explanation:

7.2 + 8.5 + 7.0 + 8.1 + 6.7 = 37.5

37.5÷5 = 7.5

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For a quadrilateral to be a parallelogram, its opposite sides and _____ must be congruent.
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<span>opposite sides and _____ </span>and angles 
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What is the product of StartFraction 4 Over 5 EndFraction times two-fifths? A model representing StartFraction 4 Over 5 EndFract
Anuta_ua [19.1K]

Answer:

StartFraction 8 Over 25

Step-by-step explanation:

What is the product of StartFraction 4 Over 5 EndFraction times two-fifths?

Mathematically =

StartFraction 4 Over 5 EndFraction = 4/5

Two- fifths = 2/5

Hence,

The product of StartFraction 4 Over 5 EndFraction times two-fifths

= 4/5 × 2/5

= 8/25

The correct option =

StartFraction 8 Over 25 EndFraction

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A bakery sells rolls in units of a dozen. The demand X (in 1000 units) for rolls has a gamma distribution with parameters α = 3,
bearhunter [10]

Answer:

The value  is  E(X) =  \$ 1.7067

Step-by-step explanation:

From the question we are told that

   The  parameters  are  α = 3, θ = 0.5

    The cost of making a unit on the first day  is  c = $2

    The selling price of a  unit on the first day is  s = $5

    The selling price of a leftover unit on the second day is  v  = $ 1

Generally the profit of a unit on the first day is

        p_1 = 5 - 2

           p_1 = \$3

The profit of a unit on the second day is

       p_2 = 1 - 2

=>     p_2 = - \$1

Generally the probability of making profit greater than $ 1 is mathematically represented as

    P(X >  1 ) = Gamma (X ,\alpha , \theta)

=>   P(X >  1 ) = Gamma (1 ,3 , 0.5)

Now from the gamma distribution table  we have that

    P(X >  1 ) =  0.67668

Generally the probability of making profit less than or  equal to  $ 1 is mathematically represented as

       P(X \le  1 ) = 1 - P(X >  1 )

=>     P(X \le  1 ) = 1 - 0.67668

=>     P(X \le  1 ) = 0.32332    

So  the probability of making  $3  is    P(X >  1 ) =  0.67668

and  the probability of making  -$1  is   P(X \le  1 ) = 0.32332  

Generally the value of profit per day is mathematically represented as

      E(X) =  3 *  P(X >  1 )   +   (-1  *  P(X \le 1 ) )

=>     E(X) =  3 * 0.67668   +   (-1  *  0.32332 )

=>     E(X) =  \$ 1.7067

4 0
1 year ago
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