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2 years ago

Don't understand this Please help asap

Mathematics

1 answer:

madam [21]2 years ago

8 0

This is easy what do you need help with?

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There are 12 girls and 10 boys in Mrs. Jones kindergarten class. How many ways can she choose a line leader and caboose each day

pshichka [43]

Answer:

choose 2 friends from 22 friends, we have 231 options

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2 years ago

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Toner cartridges for the laser printer in your office cost $90 each, including tax. You receive an $8 refund for each empty cart

dimulka [17.4K]

Step One
Figure out the cost for 1 cartridge
Cost = 90
Refund = 8 Subtract
Net cost = 82

Step Two
Find the cost for 14
14 * 82 = 1148 <<<<<< Cost for 14

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2 years ago

What is the cube root of -729a9b6

Harman [31]

ANSWER

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = - 9 {a}^{3} {b}^{2}$

EXPLANATION

We want to find the cube root of

$- 729 {a}^{9} {b}^{6}$

We express this symbolically as:

$\sqrt[3]{- 729 {a}^{9} {b}^{6} }$

The expression under the radical called the radicand.

We need to express this radical in exponential form using the property,

${x}^{ \frac{m}{n} } = \sqrt[n]{ {x}^{m} }$

Applying this rule gives us:

$\sqrt[3]{- 729 {a}^{9} {b}^{6} } = ({- 729 {a}^{9} {b}^{6}})^{ \frac{1}{3} }$

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = ({- {9}^{3} {a}^{9} {b}^{6}})^{ \frac{1}{3} }$

Recall that

$({a}^{m} )^{n} = {a}^{mn}$

We apply this rule on the RHS to get,

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = ({- {9}^{3 \times { \frac{1}{3} } } {a}^{9 \times { \frac{1}{3} } } {b}^{6 \times { \frac{1}{3} } }})$

This simplifies to

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = - 9 {a}^{3} {b}^{2}$

3 0

2 years ago

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Find a right triangle that has legs with your irrational Lengths and a hypotenuse with a rational Length

cluponka [151]

gg easy

the legs of a triangle are related as $a^2+b^2=c^2$ wehre a, b, and c are the legs and the hypotonuse of a triangle respectively

let's find some stuff

one easy way is to find a rational value for c find values of a and b

lets pick c=5

$a^2+b^2=5^2$

$a^2+b^2=25$

now split up 25 into 2 things that don't have rational square roots

if we say $a^2=19$ and $b^2=6$ then we get

$a=\sqrt{19}$ and $b=\sqrt{6}$ (which are both irrational)

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2 years ago

Julius earns $47,800 a year working for a delivery service. He is single and pays $2,152.60 in state income

ludmilkaskok [199]

Answer:

its the answer in photograph

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