4(3x-8)-4 = 24

The power 3 Superscript negative 3 equals StartFraction 1 Over 27 EndFraction . Which expression is equivalent to 3 Superscript

SpyIntel [72]

Answer:

Option a: \frac{m^{5} }{162n} is the equivalent expression.

Explanation:

The expression is \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } where m\neq 0, n\neq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }

Cancelling the like terms, we have,

\frac{3^{-3}m^{5} n^{-1}}{6 }

This equation can also be written as,

\frac{m^{5}}{3^{3}6 n^{1} }

Multiplying the terms in denominator, we have,

\frac{m^{5} }{162n}

Thus, the expression which is equivalent to \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } is \frac{m^{5} }{162n}

Hence, Option a is the correct answer. 23

Step-by-step explanation:

4 0

2 years ago

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According to the Rational Root Theorem, which statement about f(x) = 66x4 – 2x3 + 11x2 + 35 is true? Any rational root of f(x) i

Kamila [148]

Answer:

The correct option is Any rational root of f(x) is a factor of 35 divided by a factor of 66....

Step-by-step explanation:

According to the rational root theorem:

if $a_{0}$ and $a_{n}$ are non zero then each rational solution x will be:

x= +/- Factors of $a_{0}$ / Factors of $a_{n}$

In the given polynomial we have:

66x4 – 2x3 + 11x2 + 35

$a_{0}$ = 35

$a_{n}$ = 66

Therefore,

x= +/- Factors of 35/ Factors of 66.

Thus the correct option is Any rational root of f(x) is a factor of 35 divided by a factor of 66....

3 0

2 years ago

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Dee's credit card has an APR of 17% calculated on the previous monthly balance, and Dee makes a payment of $50 every month. Her

Bess [88]

Where is the table..? You didn't provide any pictures..

8 0

2 years ago

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If x and y are two positive real numbers such that x 2 +4y 2 =17 and xy =2, then find the value of x- 2y. a. 3 b. 4 c. 8 d. 9

Dafna11 [192]

Answer: The value of x- 2y is a. $\pm 3$ .

Step-by-step explanation:

Given: x and y are two positive real numbers such that $x^2+4y^2=17$ and $xy= 2$ .

Consider $(x-2y)^2=x^2-2(x)(2y)+(2y)^2\ \ \ [(a+b)^2=(a^2-2ab+b^2)]$

$=x^2-4xy+4y^2$

$=x^2+4y^2-4(xy)$

Put $x^2+4y^2=17$ and $xy= 2$ , we get

$(x-2y)^2=17-4(2)=17-8=9$

$\Rightarrow\ (x-2y)^2=9$

Taking square root on both sides , we get'

$x-2y= \pm3$

Hence, the value of x- 2y is a. $\pm 3$ .

7 0

2 years ago

At the town carnival Darren rode the ferris wheel seven times and the bumper cars three times. if each ride cost five tickets. a

stira [4]

Answer:

$10.5

Step-by-step explanation:

3 0

2 years ago