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2 years ago

Solve the following inequality. -3.55g<-28.4 which graph shows the correct solution?

Mathematics

2 answers:

Sidana [21]2 years ago

6 0

Answer:

Step-by-step explanation:

Ulleksa [173]2 years ago

5 0

Answer:

Step-by-step explanation:

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Use the alternative curvature formula K=|a x v|/|v|^3 to find the curvature of the following parameterized curves.

neonofarm [45]

Answer:

$K=\frac{2}{(4t^{2}+1)^{\frac{3}{2}}}$

Step-by-step explanation:

First of all, we calculate v and a as:

$v(t)=\frac{dr(t)}{dt}=(2t,1,0)$

$a(t)=\frac{dv(t)}{dt}=(2,0,0)$

after that, we compute the cross product and we replace in the formula for k

a(t) X v(t) = (0,0,2)

| a(t) X v(t) | = 2

$| v |^{3} = (4t^{2}+1)^{\frac{3}{2}}$

Hence we have

$K=\frac{2}{(4t^{2}+1)^{\frac{3}{2}}}$

I hope this is useful for you

regards

8 0

2 years ago

A 60-year old customer has a 401(k) account with your firm that has $280,000, mainly invested in growth mutual funds. The custom

KiRa [710]

Answer:

Money Market Instruments

Step-by-step explanation:

Money market instruments can be defined as a form of securities that help to provide businesses, banks as well as the government with large sum of amounts of low-cost capital for a short period of time because the financial markets tend to meet longer-term cash needs while Businesses tend to need short-term cash due to the fact that payments for goods and services sold might take months which is ‘Money Market’ are often been used to help to define a market where short-term financial assets are traded because they aim to increase the financial liquidity of a businesses company's or organization's.

The best recommendation to the customer is to invest the $100,000 in: MONEY MARKET INSTRUMENTS

6 0

2 years ago

A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave

erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, $L$ = 120 cm

Its wavelength $\lambda_1$ = 480 cm

$\lambda_2$ = 160 cm and $\lambda_3$ = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

The fundamental wavelength of a pipe which is open at both ends is 2L.
The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ $4L=4(120)=480\ cm$

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒ $\lambda_2=\frac{4L}{3}$ ⇒ $\lambda_3=\frac{4L}{5}$

⇒ $\lambda_2=\frac{4(120)}{3}$ ⇒ $\lambda_3=\frac{4(120)}{5}$

⇒ $\lambda_2=\frac{480}{3}$ ⇒ $\lambda_3=\frac{480}{5}$

⇒ $\lambda_2=160\ cm$ ⇒ $\lambda_3=96\ cm$

So the pipe is open at one end and closed at one end .

6 0

2 years ago

The given family of functions is the general solution of the differential equation on the indicated interval. find a member of t

Ilia_Sergeevich [38]

Try this option (see the attachment), if it is possible check result in other sources.

3 0

2 years ago

Read 2 more answers

Alinethatincludesthepoint(6, 3)hasaslopeof 2 . what isitsequationin slope -intercept form?

Marianna [84]

Hi Kay, the point-slope form of a line is given by: y - y1 = m(x - x1). Substituting the given point, (6, -8), and the slope, -2, gives: y - (-8) = -2 * (x - 6) This becomes: y + 8 = -2x + 12

3 0

2 years ago