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2 years ago

13

Nina’s sister has 386 stickers that she wants to put in a book. Each page can hold 42 stickers. How many pages will she need? Ex

plain your reasoning.

2 answers:

kap26 [50]2 years ago

5 0

Answer:

10 pages

Step-by-step explanation:

386/42=9.1 pages

but you can not have .1 of a page so you add another page.

rodikova [14]2 years ago

4 0

Answer: 10

Explanation: 386/42 = 9.1 and you can’t have .1 of a page so you add one more page

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A computer is normally $899 but is discounted to $799. What percent of the original price does Shawn pay?

Oksi-84 [34.3K]

<span>A computer is normally $899 but is discounted to $799.
Question: What percent of the original price does Shawn pay?
=> 799 dollars is the discounted price
=> 899 dollars is the original price
=> 899 – 799 = 100 dollars – the discount price that was deducted to the original price.
Solution
=> 100 / 899 = 0.11
=> 0.11 * 100% = 11%
Thus, the computer has a discount of 11%.</span>

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2 years ago

Two boats depart from a port located at (–8, 1) in a coordinate system measured in kilometers and travel in a positive x-directi

miss Akunina [59]

Answer:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

Step-by-step explanation:

1st boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a$

Equation:

$y=ax^2 -2ax+c$

The y-coordinate of the vertex:

$y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-2a\cdot (-8)+c\\ \\80a+c=1$

Solve:

$c=10+a\\ \\80a+10+a=1\\ \\81a=-9\\ \\a=-\dfrac{1}{9}\\ \\b=-2a=\dfrac{2}{9}\\ \\c=10-\dfrac{1}{9}=\dfrac{89}{9}$

Parabola equation:

$y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}$

2nd boat:

Parabola equation:

$y=ax^2 +bx+c$

The x-coordinate of the vertex:

$x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=0\\ \\b=0$

Equation:

$y=ax^2+c$

The y-coordinate of the vertex:

$y_v=a\cdot 0^2+c\Rightarrow c=-7$

Parabola passes through the point (-8,1), so

$1=a\cdot (-8)^2-7\\ \\64a-7=1$

Solve:

$a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7$

Parabola equation:

$y=\dfrac{1}{8}x^2 -7$

System of two equations:

$\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.$

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2 years ago

Read 2 more answers

The right arrow symbol used to show the transition from a point to its image after a transformation is not contained within the

Bumek [7]

Given:

Vertices of triangle ABC are A (1,4), B(3,−2) and C(4,2).

Triangle ABC reflected over the x-axis to get the triangle A'B'C'.

To find:

The coordinates of the image A'B'C'.

Solution:

If a figure reflected over the x-axis, then rule of transformation is

$(x,y)\to (x,-y)$

Now, using this rule, we get

$A(1,4)\to A'(1,-4)$

$B(3,-2)\to B'(3,2)$

$C(4,2)\to C'(4,-2)$

Therefore, the coordinates of the image A'B'C' after a reflection over the x-axis are A'(1,-4), B'(3,2) and C'(4,-2).

7 0

2 years ago

A cake manufacturer boxes Swiss chocolate and German chocolate cakes at one site. A box of Swiss chocolate cake contains 0.55 lb

Kobotan [32]

Answer:

2,500 German chocolate cake boxes.

1,500 Swiss chocolate cake boxes.

Step-by-step explanation:

Let 'S' be the number of Swiss chocolate cakes boxed and 'G' the number of German cholocate cakes boxed. If all of the available ingredients are used:

$0.55*S +0.59*G = 2,300\\0.45*S+0.41*G = 1,700$

Solving the linear system above:

$(0.55 *S +0.59*G)- \frac{0.55}{0.45} (0.45*S+0.41*G)= 2,300-\frac{0.55}{0.45}*1,700*\\0.088888*G = 222.222\\G=2,500\\S =\frac{2,300-2,500*0.59}{0.55}\\S=1500$

2,500 German chocolate cake boxes and 1,500 Swiss chocolate cake boxes can be made each day.

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2 years ago

Find the quotient 4^10/4^2

Tanya [424]

Answer:65536

4^10/4^2

4*4=16

4*4*4*4*4*4*4*4*4*4=1048576

1048576/16=65536

3 0

2 years ago