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murzikaleks [220]
2 years ago
3

He tables show the numbers of white and yellow flowers Cara and Hector used in 5 different arrangements.

Mathematics
2 answers:
Alja [10]2 years ago
8 0
Yes it is proportional
zavuch27 [327]2 years ago
4 0

Answer:

i dunno

Step-by-step explanation:

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The number of bees that visit a plant is 500 times the number of years the plant is alive, where t represents the number of year
user100 [1]

here we have given that number of bees visit a plant id 500 times the number of years that the plant is alive.

we know that t is the number of years that plant is alive.

we know that 500*t is expression representing the number of bees that will visit the plant in its life time.

5 0
2 years ago
What else would need to be congruent to show that abc def by aas
Brut [27]

Answer:

your answer is c


Step-by-step explanation:


3 0
2 years ago
Read 2 more answers
Sam and Annika ride their bikes to school. Sam rides his bike (k) kilometers . Annika rides her bike 2 less than 4 times as many
BaLLatris [955]
4(k-2) when it says 2 less than it means you are subtracting from the constant and 4 times means you are multiplying the whole equation with 4.
6 0
2 years ago
Which of the following is the graph of y = negative StartRoot x EndRoot + 1? On a coordinate plane, an absolute value curve curv
mestny [16]

Answer:

  • B. On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.

Step-by-step explanation:

<u>Graph of the function:</u>

  • y = -√x + 1

The domain is x ≥ 0, the range y ≤ 1

Correct answer choice is B

  • On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.

<em>The graph is attached</em>

7 0
2 years ago
Read 2 more answers
A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe
xxMikexx [17]

Answer:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

Step-by-step explanation:

For the random variable N_1 we define the possible values for this variable on this case [1,2,3,4,5] . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable N_1 like this:

P(N_1 = a) = \frac{5-a C 1}{5C2}

For the distribution of N_2 we need to take in count that we are finding a conditional distribution. N_2 given N_1 =a, for this case we see that N_2 \in [1,2,...,5-a], so then exist 5-a C 1 ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}

And if we want to find the joint probability we just need to do this:

P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)

And if we multiply the probabilities founded we got:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

8 0
2 years ago
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