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luda_lava [24]
2 years ago
9

What is the specific heat of copper if a 75.0 gram sample is heated from 20.0 to 24.0 by adding 117 J?

Chemistry
2 answers:
vladimir1956 [14]2 years ago
8 0

Answer:

Ahh Ive had that ill look back.

Explanation:

koban [17]2 years ago
8 0
0.39 J/g•c Please give brainliest if it doesn’t trouble you

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Which reactants would lead to a spontaneous reaction?
balandron [24]

Answer: Option (b) is the correct answer.

Explanation:

The elements which have excess or deficiency of electrons will react readily.

Atomic number of Mn is 25 and electronic configuration of Mn^{2+} is [Ar]4s^{0}3d^{5}. This configuration is stable.

Atomic number of Cr is 24 and electronic configuration of Cr is [Ar]4s^{1}3d^{5}. This configuration is not stable.

Atomic number of Fe is 26 and electronic configuration of Fe is [Ar]4s^{2}3d^{6}. This configuration is stable.

Atomic number of Cu is 29 and electronic configuration of Cu^{2+} is [Ar]4s^{0}3d^{9}. This configuration is not stable.

Atomic number of Al is 13 and electronic configuration of Al is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}. This configuration is not stable.

Atomic number of Ba is 56 and electronic configuration of Ba^{2+} is [Kr]4d^{10}5s^{2}5p^{6}. This configuration is stable.

Atomic number of Mg is 12 and electronic configuration of Mg^{2+} is 1s^{2}2s^{2}2p^{6}. This configuration is stable.

Atomic number of Sn is 50 and electronic configuration of Sn is [Kr]4d^{10}5s^{2}5p^{2}. This configuration is stable.

Thus, we can conclude that out of the given options, only Fe and Cu^{2+} reactants would lead to a spontaneous reaction as they have incomplete sub-shells. Therefore, in order to gain stability they will readily react.


8 0
2 years ago
Empirical Formula of P3O4H2?
puteri [66]

Answer:

H2 P4 O1. Explanation: In order to calculate the Empirical formula , we will assume that we have started with 10 g of the compound.

Explanation:

3 0
2 years ago
How many moles of chromium(iii) nitrate are produced when chromium reacts with 0.85 moles of lead(iv) nitrate to produce chromiu
Alexxandr [17]
The  moles  of  chromium (iii)  nitrate  produced  is  calculated  as   follows

write  the  equation  for  reaction

 3  Pb(NO3)2  +  2 Cr  =  2 Cr(NO3)3  +  3  Pb

by  use  of  mole  ratio  between  Pb(NO3)2  to  Cr(NO3)3  which  is  3  :  2  the  moles  of  Cr(NO3)3  is therefore  
=  0.85  x2  /3  =  0.57   moles
5 0
2 years ago
How long would it take for 1.50 mol of water at 100.0 ∘c to be converted completely into steam if heat were added at a constant
Aleksandr-060686 [28]
To determine the time it takes to completely vaporize the given amount of water, we first determine the total heat that is being absorbed from the process. To do this, we need information on the latent heat of vaporization of water. This heat is being absorbed by the process of phase change without any change in the temperature of the system. For water, it is equal to 40.8 kJ / mol.

Total heat = 40.8 kJ / mol ( 1.50 mol ) = 61.2 kJ of heat is to be absorbed

Given the constant rate of 19.0 J/s supply of energy to the system, we determine the time as follows:

Time = 61.2 kJ ( 1000 J / 1 kJ ) / 19.0 J/s = 3221.05 s
5 0
2 years ago
Read 2 more answers
In E. coli, the enzyme hexokinase catalyzes the reaction: Glucose + ATP → glucose 6-phosphate + ADP The equilibrium constant, Ke
kondor19780726 [428]

Answer:

Explanation:

Glucose + ATP → glucose 6-phosphate + ADP The equilibrium constant, Keq, is 7.8 x 102.

In the living E. coli cells,

[ATP] = 7.9 mM;

[ADP] = 1.04 mM,

[glucose] = 2 mM,

[glucose 6-phosphate] = 1 mM.

Determine if the reaction is at equilibrium. If the reaction is not at equilibrium, determine which side the reaction favors in living E. coli cells.

The reaction is given as

Glucose + ATP → glucose 6-phosphate + ADP

Now reaction quotient for given equation above is

q=\frac{[\text {glucose 6-phosphate}][ADP]}{[Glucose][ATP]}

q=\frac{(1mm)\times (1.04 mm)}{(7.9mm)\times (2mm)} \\\\=6.582\times 10^{-2}

so,

q ⇒ following this criteria the reaction will go towards the right direction ( that is forward reaction is favorable  until q = Keq

4 0
2 years ago
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