Identify the conditions for an inelastic collision in a closed system. Check all that apply.
2 answers:
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Answer:
μ = 0.350
Explanation:
For the person to able to move the box, the force exerted by the person on the box must equal the force exerted by the box:
In this case, force can be calculated as a product of mass (m) by the acceleration of gravity (g) and the coefficient of static friction (μ):
Therefore, for the person to be able to push the box horizontally, the coefficient of static friction between the box and the floor should not be higher than 0.350.
The given question is incomplete. The complete question is as follows.
A 6.70 −μC particle moves through a region of space where an electric field of magnitude 1500 N/C points in the positive x direction, and a magnetic field of magnitude 1.25 T points in the positive z direction.
A) If the net force acting on the particle is N in the positive x direction, find the components of the particle's velocity. Assume the particle's velocity is in the x-y plane.
Enter your answers numerically separated by commas.
Explanation:
The given data is as follows.
Q =
E = 1300 N/C in the +x direction
B = 1.02 T in the +z direction
and, in the +x direction
Also,
= qE - qvB
Now, we will calculate the value of v as follows.
v =
=
v = 458.507 m/s
Using the value for velocity, we need to know which direction it's going.
You know +x direction for E, +z direction for B and +x for .
Using the right hand rule where:
your right thumb goes toward the , then your index finger points to B (z direction) Then curl your middle, ring, and pink 90 angle. This shows where v is going which is -y direction.
Thus, we can conclude that = 0, -(458.507), 0.