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2 years ago

Find the perimeter of a circle whose diameter is 12.6 cm please help and show working

Mathematics

2 answers:

soldi70 [24.7K]2 years ago

8 0

Answer:

39.584034 cm

Step-by-step explanation:

Firstly find the radius, 6.3 cm. Then plug into the formula, 2πr.

I used 3.14159 as pi.

work:

2 * 3.14159 * 6.3

6.28318 * 6.3

39.584034

ycow [4]2 years ago

3 0

Do you mean the circumference? You can’t find the perimeter of a circle. The circumstance of the circle is 39.584 to 3dp.

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The fish population in a pond with carrying capacity 1200 is modeled by the following logistic equation where N(t) denotes the n

MArishka [77]

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Answer:

(dN)/(dt) = (0.4)/(1200)N(1200-N) -50

142 fish

Step-by-step explanation:

A) The differential equation is modified by adding a -50 fish per year constant term:

(dN)/(dt) = (0.4)/(1200)N(1200-N) -50

B) The steady-state value of the fish population will be when N reaches the value that makes dN/dt = 0.

(0.4/1200)(N)(1200-N) -50 = 0

N(N-1200) = -(50)(1200)/0.4) . . . . rewrite so N^2 has a positive coefficient

N^2 -1200N + 600^2 = -150,000 +600^2 . . . . complete the square

(N -600)^2 = 210,000 . . . . . simplify

N = 600 + √210,000 ≈ 1058

This steady-state number of fish is ...

1200 - 1058 = 142 . . . . below the original carrying capacity

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2 years ago

14 birds were sitting in a tree 21 more birds flew up to the tree how many birds were there altogether in the tree ?

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Which model represents the factors of x2 + 9x + 8?

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In order to estimate the average electricity usage per month, a sample of 125 residential customers were selected, and the month

mr_godi [17]

Answer:

[895.05; 940.81]kWh

Step-by-step explanation:

Hello!

Be X: monthly electricity usage by a residential customer

X~N

σ²: 12100KWh²

To estimate the population mean using a 98% CI you have to use the following formula

[X[bar]± $Z_{1-\alpha /2}$ * $\frac{Sigma}{\sqrt{n} }$ ]

1-α: 0.98

α0.02

α/2: 0.01

1-α/2:0.99

$Z_{1-\alpha /2}= Z_{0.99}= 2.326$

n= 125

X[bar]= ∑X/n= 228565/125= 917.93

[917.93±2.326 * $\frac{110}{\sqrt{125} }$ ]

[895.05; 940.81]

Using a 98% confidence level you'd expect that the interval [895.05; 940.81]kWh will include the average monthly electricity usage of residential customers.

I hope this helps!

Raw data:

Electric Usage

765

1139

714

687

1027

1109

749

799

911

631

975

717

1232

806

637

894

856

896

1272

1224

621

606

898

723

817

746

933

595

851

1027

770

685

750

1198

975

678

1050

886

826

1176

583

841

1188

692

733

791

584

1163

593

1234

603

1044

1233

1178

598

904

778

693

590

845

893

1028

975

788

1240

1253

854

1185

1164

741

1058

1053

795

1198

1240

1140

959

938

1008

1035

1085

1100

680

1006

977

1042

1252

943

1165

1014

912

791

612

935

864

953

667

1005

1063

1095

1086

810

1032

970

1099

1229

892

1074

579

754

1007

1116

583

763

1231

966

962

1132

738

1033

697

891

840

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2 years ago

Michael needs to pay car insurance premiums of $958 two times per year. He has decided to make deposits from each paycheck to a

nata0808 [166]

Given: Car insurance premium in a first half year = $958

Car insurance premium in the second half year = $958

Total Car insurance premium in year = 2 × $958 = $ 1916

Nature of paid premium is bi-weekly = in 2 weeks

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Total deposited amount per bi-weekly = $ 1916 ÷ 26 =$ 73.69 ≈ $ 74

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2 years ago

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Find the perimeter of a circle whose diameter is 12.6 cm please help and show working​

Find the perimeter of a circle whose diameter is 12.6 cm please help and show working