What is 1.9541 rounded to the nearest thousandth

Which equation can you use to solve in the figure shown?

Neporo4naja [7]

What’s the figure I couldn’t see anything here.

5 0

2 years ago

Work out ( 8x10 -3) x(2x10 -4) standard form

zheka24 [161]

Answer: 1232

Step-by-step explanation: ( 8x10 -3) x(2x10 -4)

( 8x10 -3) = 77

(2x10 -4) = 16

77 x 16 = 1232

Answer = 1232

4 0

2 years ago

A bakery sells rolls in units of a dozen. The demand X (in 1000 units) for rolls has a gamma distribution with parameters α = 3,

bearhunter [10]

Answer:

The value is $E(X) = \$ 1.7067$

Step-by-step explanation:

From the question we are told that

The parameters are α = 3, θ = 0.5

The cost of making a unit on the first day is c = $2

The selling price of a unit on the first day is s = $5

The selling price of a leftover unit on the second day is v = $ 1

Generally the profit of a unit on the first day is

$p_1 = 5 - 2$

$p_1 = \$3$

The profit of a unit on the second day is

$p_2 = 1 - 2$

=> $p_2 = - \$1$

Generally the probability of making profit greater than $ 1 is mathematically represented as

$P(X > 1 ) = Gamma (X ,\alpha , \theta)$

=> $P(X > 1 ) = Gamma (1 ,3 , 0.5)$

Now from the gamma distribution table we have that

$P(X > 1 ) = 0.67668$

Generally the probability of making profit less than or equal to $ 1 is mathematically represented as

$P(X \le 1 ) = 1 - P(X > 1 )$

=> $P(X \le 1 ) = 1 - 0.67668$

=> $P(X \le 1 ) = 0.32332$

So the probability of making $3 is $P(X > 1 ) = 0.67668$

and the probability of making -$1 is $P(X \le 1 ) = 0.32332$

Generally the value of profit per day is mathematically represented as

$E(X) = 3 * P(X > 1 ) + (-1 * P(X \le 1 ) )$

=> $E(X) = 3 * 0.67668 + (-1 * 0.32332 )$

=> $E(X) = \$ 1.7067$

4 0

2 years ago

In a statewide soccer competition, 36 games were played. Each team participating in the competition played once with every other

Tomtit [17]

Answer:

9 teams

Step-by-step explanation:

If the total games played was 36 and no team played each other twice, we need to ensure there isn't any double counting.

36 = (n-1) + (n-2) + (n-3) ... + (n-(n-1))

using this knowledge, we can then count up:

1+2+3+4+5+6+7+8 = 36

If our highest number is 8, then we know there must be 9 teams, because no team can play themselves.

8 0

2 years ago

Read 2 more answers

A community hall is in the shape of a cuboid the hall is 40m long 15m high and 3m wide. 10 litre paint covers 25m squared costs

Darina [25.2K]

Answer:

Total cost for tiles and paints is $924.

Step-by-step explanation:

We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.

The paint will be required for 4 walls and ceiling.

Let us find area of walls and ceiling.

$\text{Area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)$

$\text{Area of walls and ceiling}=1200+90+120$

$\text{Area of walls and ceiling}=1410$

Therefore, the area of walls and ceiling is 1410 square meters.

Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,

$\text{ The total painting cost}=10*(\frac{1410}{25})$

$\text{ The total painting cost}=10*56.4=564$

Therefore, the total painting cost is $564.

Tiles will be required for floor. Let us find the area of floor.

$\text{Area of floor} = 40*3\text{ square meters}$

$\text{Area of floor} =120\text{ square meters}$

Given: 1m squared floor tiles costs $3. So,

$\text{Total cost for tiles} = 3*120 = 360$

Therefore, the total tiles cost is $360.

Now let us find combined total cost of tiles and paint.

$\text{Combined total cost}= 564+360 = 924$

Therefore, the combined total cost of tiles and paint is $924.

6 0

2 years ago