Answer:
Largest possible length is <em>21 inches</em>.
Step-by-step explanation:
Given:
Total material available = 60 inches
Length to be 3 more than twice of width.
To find:
Largest possible length = ?
Solution:
As it is rectangular shaped frame.
Let length = 
inches and
Width = 
inches
As per given condition:
..... (1)
Total frame available = 60 inches.
i.e. it will be the perimeter of the rectangle.
Formula for perimeter of rectangle is given as:
Putting the given values and conditions as per equation (1):
Putting in equation (1):
So, the answer is:
Largest possible length is <em>21 inches</em>.
Answer:
10.55% probability
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which the CDs are chosen is not important. So we use the combinations formula to solve this question.
1 Bach CD, from a set of 4.
1 Beethoven CD, from a set of 6.
1 Brahms CD, from a set of 3.
1 Handel CD, from a set of 2.
So, D=144
4 CDs from a set of 4+6+3+2 = 15.
So, T= 1365
p= D/T= 144/1365 = 0.1055
10.55% probability that she will choose one by each composer
1.5r+15=2.25r
First of all, you have to arrange the numbers according to those similar to them. So that will be;
15=2.25r-1.5r
1.5r is subtracted from 2.25r because it crossed over an equality sign to get its position close to 2.25r. And when a number crosses over an equality sign, the sign on the number chages to the opposite. 1.5r has an invisible positive sign which became negative when it crossed. Anyway;
2.25r-1.5r is the same as 2.25-1.5. And that is 0.75r
Therefore;
15=0.75r
To find out what r is, you have to divide the both sides by 0.75. This is done to remove the 0.75 close to r to finally reveal what r is. Anyway;
15/0.75=0.75r/0.75
15 divided by 0.75 is 20. And 0.75r divided by 0.75 is r. So;
20=r
r=20. So the answer is 20 movies. Hope i helped. Have a nice day.
Then, 15 - x is the distance ran in the second part.
The time, t1, for the first part is t1 = xmi / 8mi/h
The time, t2, for the second part is t2 = (15 - x)mi / 20mi/h
The total time is t1 + t2 = 1.125 h
Then x/8 + (15 - x) / 20 = 1.125
To solve for x, multiply both sides by 40 (this is the least common multiple)
5x + 30 - 2x = 45
3x = 15
to find x divide: 15/3=5
And 15 - x = 10 mi.
First part:
Speed: 8mi/h
Distance: 5 mi
Time: 5mi/8mi/h = 5/8 h = 37.5 minutes
Second part
Speed: 20 mi/h
Distance: 10 mi
Average speed: 15mi/1.125h =13.33 mi/h
Distance: 15mi
Time: 1.125 h = 67.5 minutes
