Answer: The answer is 0.33
Explanation: got the question right :)
Thank you for posting your question here at brainly. Below is the solution:
To find the circumference (orbit) of an object, you use Pi x Diameter.
<span>As you have the circumference of B, you divide it by Pi to get the Diameter. </span>
<span>So 120 divided by 3.141592654 = 38.2 minutes for the Diameter. </span>
<span>As' radius and Diameter will be 3x greater than B. </span>
<span>38.2 x 3 = 114.6 </span>
<span>To get back to the orbital period, times 114.6 by Pi, and you will get 360 minutes. </span>
Net flux through the cylindrical surface is given as

here q = enclosed charge in the surface
so here in order to find the value of q

so now we have

so this is the total flux
now by Gauss's law we can find the electric field




<em>by above expression we can find the electric field at required position</em>
- The horizontal pushing force required to just start the crate moving is 447 N.
- The horizontal pushing force required to slide the crate across the dock at a constant speed is 241 N.
<u>Explanation</u>:
- By the definition of the coefficient of static friction we have:
μ
=
,
where,
is the horizontal pushing force,
W = mg is the weight of the crate directed downward,
is the static friction force-directed opposite to the horizontal pushing force and equal to it,
N is the force of reaction directed upward and equal to the weight of the crate.
From this formula we can find the horizontal pushing force required to just start the crate moving:
= 0.760
60 kg
9.8 m / s^2
= 447 N.
- By the definition of the coefficient of kinetic friction we have:
u
,
where,
is the horizontal pushing force,
W = mg is the weight of the crate directed downward,
is the kinetic friction force-directed opposite to the horizontal pushing force and equal to it,
N is the force of reaction directed upward and equal to the weight of the crate.
From this formula we can find the horizontal pushing force required to slide the crate across the dock at a constant speed:
= 0.410
60
9.8
= 241 N.
- The horizontal pushing force required to just start the crate moving is 447 N.
- The horizontal pushing force required to slide the crate across the dock at a constant speed is 241 N.
Answer:
4.
Explanation:
Given,
frequency of standing wave = 603 Hz
length of string,L = 1.33 m
speed of the wave, v = 402 m/s
number of antinodes = ?
Wavelength of the standing wave



Number of anti nodes in the standing wave



n =3.97= 4.
Number of antinodes is equal to 4.