Answer:
The coefficient of static friction between the puppy and the floor is 0.7273.
Explanation:
The horizontal force applied to move the puppy from a steady state has to be greater than the force of static friction, after it is moving the force needs to be equal to be greater than the force of dynamic friction in order to maintain its movement. The force of static friction is given by:
Where 
is the static friction force, 
is the coefficient of static friction and 
is the normal force. Since there's no angle on the flor the normal force is equal to the weight of the puppy, therefore, 
, to make the puppy moving we need to use a force of 80 N, therefore, 
, so we can solve for the coefficient as shown below:
The coefficient of static friction between the puppy and the floor is 0.7273.
Answer:
6N
Explanation:
Given parameters:
Pressure applied by the woman = 300N/m²
Area = 0.02m²
Unknown:
Force applied = ?
Solution:
Pressure is the force per unit area on a body
Pressure = 
Force = Pressure x area
Force = 300 x 0.02 = 6N
Answer:
option A
Explanation:
given,
depth of the sea level = 10 m
g = 10 m/s²
Pressure underwater = ?
we know,
P = ρ g h
where ρ is the density of water which is equal to 1000 kg/m³
h is the depth of sea level
P = ρ g h
P = 1000 x 10 x 10
P = 100000 Pa
P = 100 kPa
Hence, the correct answer is option A
Use this formula
Vf = sqrt(2gh)
I made the drawing in the attached file.
I included two figures.
The upper figure shows the effect of:
- multiplying vector A times 1.5.
It is drawn in red with dotted line.
- multiplying vector B times - 3 .
It is drawn in purple with dotted line.
In the lower figure you have the resultant vector: C = 1.5A - 3B.
The method is that you translate the tail of the vector -3B unitl the point of the vector 1,5A, preserving the angles.
Then you draw the arrow that joins the tail of 1,5A with the point of -3B after translation.
The resultant arrow is the vector C and it is drawn in black dotted line.
