answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kazeer [188]
2 years ago
10

A sleepy student drops a calculator out of a window that's 20.7\text{ m}20.7 m20, point, 7, start text, space, m, end text off t

he ground. We can ignore air resistance.
What is the velocity of the calculator after falling for 1.8\,\text s1.8s1, point, 8, start text, s, end text?
Physics
1 answer:
Ira Lisetskai [31]2 years ago
8 0

Answer:

Explanation:

You can ignore how high the window actually is, unless the calculator falls further.  You just want to use the formula v_f = v_i + at  Let em know if that doesn't help and I can work you through it.

To check the distance use y = v_i*t + .5at^2.  Would just plug in 0*1.8 + .5(-9.8)1.8^2 = -15.876, so it doesn't fall more than 20.7 m so indeed, you don't have to worry about that.  

Again, let me know if you need further help.

You might be interested in
In a movie, Tarzan evades his captors by hiding under water for many minutes while breathing through a long, thin reed. Assume t
gladu [14]

Answer: 0.98m

Explanation:

P = -74 mm Hg = 9605 Pa = 9709N/m^2

= 9605 kg m/s^2/m^2

density of water: rho = 1 g/cc = 1 (10^-3 kg)/(10^-2 m)^-3 = 1000 kg/m^3

Pressure equation: P = rho g h

h = P/(rho g)

h = (9605 kg/m/s^2) / (1000 kg/m^3) / (9.8 m/s^2)

h = 0.98 m

0.98m is the maximum depth he could have been.

8 0
2 years ago
refrigerant 134a enters a compressor operating at steady state as saturated vapor at 0.12 MPa and exits at 1.2 MPa and 70 C at a
Afina-wow [57]

Answer:

the power input to the compressor is 7.19Kw

Explanation:

Hello!

To solve this problem follow the steps below.

1. We will call 1 the refrigerant state at the compressor inlet and 2 at the outlet.

2. We use thermodynamic tables to determine enthalpies in states 1 and 2.

(note: Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)  

through prior knowledge of two other properties such as pressure and temperature.  )

h1[quality=1, P=0.12Mpa)=237KJ/Kg

h2(P=1.2Mpa, t=70C)=300.6KJ/kg

3. uses the first law of thermodynamics in the compressor that states that the energy that enters a system is the same that must come out

Q=heat=0.32kJ/s

W=power input to the compressor

m=mass flow=0.108kg/S

m(h1)+W=Q+m(h2)

solving for W

W=Q+m(h2-h1)

W=0.32+0.108(300.6-237)=7.19Kw

the power input to the compressor is 7.19Kw

7 0
2 years ago
Seven seconds after a brilliant flash of lightning, thunder shakes the house. approximately how far was the lightning strike fro
tangare [24]
Very roughly 7,700 feet ... about 1.5 miles.
8 0
2 years ago
In the equation vx^2=v0x^2+2ax(x-x0) what does the terms vx, v0x, x, and x0 stand for respectively?
tatuchka [14]

B. velocity at position x, velocity at position x=0, position x, and the original position

In the equation

v_{x}^{2} = v_{ox}^{2} +2 a x (x - x₀)

v_{x} = velocity at position "x"

v_{ox} = velocity at position "x = 0 "

x = final position

x_{o} = initial position of the object at the start of the motion

6 0
2 years ago
Read 2 more answers
A stone is thrown vertically upward with a speed of 15.0 m/s from the edge of a cliff 75.0 m high.How much later does it reach t
Katarina [22]

Answer:

5.72 seconds

848.27 m/s

97.94 m

Explanation:

t = Time taken

u = Initial velocity = 15 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow 0=15-9.81\times t\\\Rightarrow \frac{-15}{-9.81}=t\\\Rightarrow t=1.52 \s

Time taken to reach maximum height is 0.97 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow s=15\times 1.52+\frac{1}{2}\times -9.81\times 1.52^2\\\Rightarrow s=11.47\ m

So, the stone would travel 11.47 m up

So, total height stone would fall is 75+11.47 = 86.47 m

Total distance travelled by the stone would be 75+11.47+11.47 = 97.94 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 86.47=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{86.47\times 2}{9.81}}\\\Rightarrow t=4.2\ s

Time taken by the stone to travel 86.47 m to the water is is 4.2 seconds

The stone reaches the water after 4.2+1.52 = 5.72 seconds after throwing the stone

v=u+at\\\Rightarrow v=0+9.81\times 86.47 = 848.27\ m/s

Speed just before hitting the water is 848.27 m/s

3 0
2 years ago
Other questions:
  • Find the angle (above the horizontal) at which a projectile achieves its maximum range, if y=y0.
    11·1 answer
  • A uniform drawbridge must be held at a 37 ∘ angle above the horizontal to allow ships to pass underneath. the drawbridge weighs
    8·2 answers
  • You are designing a hydraulic lift for a machine shop. the average mass of a car it needs to lift is about 1500 kg. you wish to
    6·1 answer
  • What is the torque τa about axis a due to the force f⃗ ? express the torque about axis a at cartesian coordinates (0,0)?
    9·1 answer
  • The particle with charge q is now released and given a quick push; as a result, it acquires speed v. Eventually, this particle e
    10·1 answer
  • What is the tangential velocity at the edge of a disk of radius 10cm when it spins with a frequency of 10Hz? Give your answer wi
    15·1 answer
  • A steel cable lifting a heavy box stretches by ΔL . In order for the cable to stretch by only half of ΔL , by about what factor
    14·1 answer
  • when you drop a pebble from height h, it reaches the ground with kinetic energy k if there is no air resistance. from what heigh
    11·1 answer
  • What is the concentration of molecular oxygen (O2) in mol/L on a June day in Toronto when atmospheric pressure is 1.0 atm and th
    15·1 answer
  • A projectile is launched at an angle of 60° from the horizontal and at a velocity of
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!