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maw [93]
2 years ago
7

Which statement correctly describes the electrons in a water molecule?. . A.Which statement correctly describes the electrons in

a water molecule?. B.Electrons are pulled closer to the oxygen atom.. C.Electrons are located inside the nucleus of the hydrogen atoms.. D.Electrons are an equal distance between hydrogen and oxygen.
Physics
2 answers:
Zepler [3.9K]2 years ago
7 0

Answer: Option (B) is the correct answer.

Explanation:

Molecular formula of water is H_{2}O. In a water molecule, hydrogen and oxygen ions are held together by strong hydrogen bonding.

Out of hydrogen and oxygen, oxygen is more electronegative. Thus, it will attract the electrons of hydrogen atom more towards itself. As a result, a partial positive charge will develop on hydrogen atom and a partial negative charge will develop on oxygen atom.

Thus, we can conclude that the statement electrons are pulled closer to the oxygen atom correctly describes the electrons in a water molecule.

exis [7]2 years ago
4 0

The statement “Electrons are pulled closer to the oxygen atom” correctly describes the electrons in a water molecule. The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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What is the wavelength of a 100-mhz ("fm 100") radio signal?
vagabundo [1.1K]
Radio wave is about 3.10^8m/s divided by 10^8 hz is 3 nesters sound wave is 343m/s so thus Equal to approximately 0.78
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2 years ago
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A uniform Rectangular Parallelepiped of mass m and edges a, b, and c is rotating with the constant angular velocity ω around an
Sonbull [250]

Answer:

(a) k = \frac{Mw^{2} }{6} (a^{2} +b^{2} )

(b)  τ = \frac{M}{3} (a^{2} +b^{2} ) ∝

Explanation:

The moment of parallel pipe rotating about it's axis is given by the formula;

I = \frac{M}{3} (a^{2} +b^{2} )   ---------------------------------1

(a) The kinetic energy of a parallel pipe is also given as;

k =\frac{1}{2} Iw^{2} --------------------------------2

Putting equation 1 into equation 2, we have;

k = \frac{M}{6} (a^{2} +b^{2} )w^{2}

k = \frac{Mw^{2} }{6} (a^{2} +b^{2} )

(b) The angular momentum is given by the formula;

τ = Iw -----------------------3

Putting equation 1 into equation 3, we have

τ = \frac{Mw}{3} (a^{2} +b^{2} )

But

τ = dτ/dt = \frac{M}{3} (a^{2} +b^{2} )\frac{dw}{dt}   ------------------4

where

dw/dt = angular acceleration =∝

Equation 4 becomes;

τ = \frac{M}{3} (a^{2} +b^{2} ) ∝

8 0
2 years ago
At a given point on a horizontal streamline in flowing air, the static pressure is â2.0 psi (i.e., a vacuum) and the velocity is
Nastasia [14]
At a point on the streamline, Bernoulli's equation is
p/ρ + v²/(2g) = constant
where
p = pressure
v = velocity
ρ = density of air, 0.075 lb/ft³ (standard conditions)
g = 32 ft/s²

Point 1:
p₁ = 2.0 lb/in² = 2*144 = 288 lb/ft²
v₁ = 150 ft/s

Point 2 (stagnation):
At the stagnation point, the velocity is zero.

The density remains constant.
Let p₂ = pressure at the stagnation point.
Then,
p₂ = ρ(p₁/ρ + v₁²/(2g))
p₂ = (288 lb/ft²) + [(0.075 lb/ft³)*(150 ft/s)²]/[2*(32 ft/s²)
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Answer: 2.2 psi

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2 years ago
As she was trying to study, Tanisha asked her roommate to lower the radio. Her roommate had turned the radio up originally from
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Answer:

just-noticeable difference

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qaws [65]

let the length of the beam be "L"

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m = mass of beam = 20 kg

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using equilibrium of torque about B

(m₁ g) (AB) = (mg) (BC) + (m₂ g) (BD)

30 (1.10) = (20) ((L/2) - 1.10) + (40) (L - 1.10)

L = 1.98 m

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2 years ago
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