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Pani-rosa [81]
2 years ago
11

A crate is placed on an adjustable, incline board. the coefficient of static friction between the crate and the board is 0.29.

Physics
1 answer:
sasho [114]2 years ago
7 0

Let the angle be Θ (theta)

Let the mass of the crate be m.

a) When the crate just begins to slip. At that moment the net force will be equal to zero and the static friction will be at the maximum vale.

Normal force (N) = mg CosΘ

μ (coefficient of static friction) = 0.29

Static friction = μN = μmg CosΘ

Now, along the ramp, the equation of net force will be:

mg SinΘ - μmg CosΘ = 0

mg SinΘ = μmg CosΘ

tan Θ = μ

tan Θ = 0.29

Θ = 16.17°

b) Let the acceleration be a.

Coefficient of kinetic friction = μ = 0.26

Now, the equation of net force will be:

mg sinΘ - μ mg CosΘ = ma

a = g SinΘ - μg CosΘ

Plugging the values

a = 9.8 × 0.278 - 0.26 × 9.8 × 0.96

a = 2.7244 - 2.44608

a = 0.278 m/s^2

Hence, the acceleration is 0.278 m/s^2

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agasfer [191]

Answer:

m = 4.29 kg

Explanation:

Given that,

Mass of the object, m = 2.8 kg

Stretching in the spring, x = 0.018 m

Frequency of vibration, f = 3 Hz

Let m is the mass of the object that is attached to the spring. When it is attached the gravitational force is balanced by the force on spring. It is given by :

mg=kx

k=\dfrac{mg}{x}

k=\dfrac{2.8\times 9.8}{0.018}

k = 1524.44 N/m

Since, \omega=\sqrt{\dfrac{k}{m}}

m=\dfrac{k}{4\pi^2 f^2}

m=\dfrac{1524.44}{4\pi^2 \times 3^2}

m = 4.29 kg

So, the mass that is attached to this spring is 4.29 kg. Hence, this is the required solution.

4 0
2 years ago
Temperature and kinetic energy are ___________ proportional. adirectly directly indirectly 2. Heat is a measure of _____________
Usimov [2.4K]

Explanation:

It is known that relation between kinetic energy and temperature is as follows.

        K.E \propto \frac{3}{2}kT

Hence, kinetic energy is directly proportional to temperature.

Thermal energy is defined as the energy present within the molecules of an object due to the motion of particles. Basically, thermal energy is internal energy of an object.

Thus, we can conclude that:

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7 0
2 years ago
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An object is located 25.0 cm from a convex mirror. The image distance is -50.0 cm. What is the magnification?
Lynna [10]

Answer:

\boxed{\sf Magnification \ (m) = 2}

Given:

Object distance (u) = 25.0 cm

Image distance (v) = -50.0 cm

To Find:

Magnification (m)

Explanation:

\boxed{\bold{\sf Magnification  \: (m) = - \frac{Image  \: distance  \: (v)}{Object  \: distance  \: (u)}}}

Substituting values of Image distance(v) & Object distance (u) in the equation:

\sf \implies m =  -  \frac{( - 50)}{25}

-(-50) = 50:

\sf \implies m =  \frac{50}{25}

\sf \implies m =  \frac{2 \times  \cancel{25}}{ \cancel{25}}

\sf \implies m = 2

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What is the wavelength of a 100-mhz ("fm 100") radio signal?
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The following times are given using metric prefixes on the base SI unit of time: the second. Rewrite them in scientific notation
Leno4ka [110]

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b=9.8*10^-13s

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d=5.57*10^-4s

Explanation:

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Expected answer is 980 * 10^-12

Therefore, 980ps = 9.8*10^-10s

b) given 980 fs

Expected answer is 980 * 10^-15

Therefore, 980fs = 9.8*10^-13s

c) given 17 ns

Expected answer is 17 * 10^-9

Therefore, 17ns = 1.7*10^-8s

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Expected answer is 577 * 10^-6

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