A 2600-m-high mountain is located on the equator. how much faster does a climber on top of the mountain move than a surfer at a
1 answer:
The climber move 0.19 m/s faster than surfer on the nearby beach.
Since both the person are on the earth, and moves with the constant angular velocity of earth, however there linear velocity is different.
Number of seconds in a day, t=24*60*60=86400 sec
The linear speed on the beach is calculated as
V1=
Here, t is the time
Plugging the values in the above equation
V1==465.421 m/s
Velocity on the mountain is calculated as
V2=
Plugging the values in the above equation
V2==465.61 m/s
Therefore person on the mountain moves faster than the person on the beach by 465.61-465.421=0.19 m/s
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As per the question the distance travelled by a car is 28.4 inch.
we are asked to determine the conversion factor in centimeter which when multiplied with 28.4 inch will give a unit.
we know that one inch =2.54 centimeter.
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