Answer:
The question involves drawing of structures and showing mechanism in which brainly text editor did not support. I made sure I created a pdf file with both the anwsers and explanations in it. The pdf can be found in the attachment below.
Explanation:
Answer:
Explanation:
Hello,
In this case, we can compute the mole fraction of benzene by using the following formula:
Whereas n accounts for the moles of each substance, thus, we compute them by using molar mass of benzene and cyclohexane:
Thus, we compute the mole fraction:
Next, for the molality, we define it as:
Whereas we also use the moles of benzene but rather than the moles of cyclohexane, its mass in kilograms (0.08074 kg), thus, we obtain:
Or just 0.990 m in molal units (mol/kg).
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Cr{3+} + 3 NaF → CrF3 +
3 Na{+} <span>
First calculate the total mols of NaF.
(0.063 L) x (1.50 mol/L NaF) = 0.0945 mol NaF total </span>
Using stoichiometric
ratio:
<span>0.0945 mol NaF * (1 mol Cr3+ / 3 mol NaF) * (51.9961 g Cr3+/mol) =
1.6379 g Cr3+</span>
Answer:
sure
Explanation:
The substance formed after heating the mixture of that of Rahul is caleed a compound. Whereas, Manav's mixture still remains in its current stae that is a heterogeneous mixture.
The compound formed is in black in color whereas the mixture is a mix of brownish-red and yellow.
The compound is a homogeneous mixture whereas the mixture is a heterogenous mixture because of its uneven distribution.
Usually concentrations are expressed as molarity, or moles of solute per liter solution. First, convert the mass of bromide ion to moles. The molar mass of bromine is 79.904 g/mol.
Moles of bromine = 65 mg * 1 g/1000 mg * 1 mol/79.904 g = 8.135×10⁻⁴ moles
Next, convert the mass of seawater to volume using the density.
Volume of seawater = 1 kg * 1 m³/ 1,025 kg * 1000 L/1 m³ = 0.976 L
Thus,
Molarity = 8.135×10⁻⁴ moles/0.976 L = 8.335×10⁻⁴ M
