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SSSSS [86.1K]
2 years ago
13

Rahul and Manav each were given a mixture of iron filings and sulphur powder. Rahul heated the mixture strongly and a new substa

nce was formed. Write three points of difference between the two.Required to answer.​
Chemistry
1 answer:
AlexFokin [52]2 years ago
3 0

Answer:

sure

Explanation:

The substance formed after heating the mixture of that of Rahul is caleed a compound. Whereas, Manav's mixture still remains in its current stae that is a heterogeneous mixture.

The compound formed is in black in color whereas the mixture is a mix of brownish-red and yellow.

The compound is a homogeneous mixture whereas the mixture is a heterogenous mixture because of its uneven distribution.

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Which of the following statements is true about the following reaction?
MAVERICK [17]

The correct reaction equation is:

3NaHCO_{3} (aq) + C_{6}H_{8}O_{7} (aq) \rightarrow 3CO_{2} (g) + 3H_{2}O (l) + Na_{3}C_{6}H_{5}O_{7} (aq)

Answer:

b) 1 mole of water is produced for every mole of carbon dioxide produced.

Explanation: <u>CONVERT EVERYTHING TO MOLES OR VOLUME, THEN COMPARE IT WITH THE COMPOUND'S STOICHIOMETRY IN CHEMICAL EQUATION.</u>

a) <u>22.4 L of CO_{2} gas</u> is produced only when <u>\frac{22.4}{3} L of  C_{6}H_{8}O_{7}</u> is reacted with 22.4 L of NaHCO_{3}. So it is wrong.

b) Since in the chemical equation the stoichiometric coefficient of CO_{2}  and H_{2}O are same so the number of moles or volume of each of them will be same whatever the amount of reactants taken. <u>Therefore it is correct option.</u>

c)  6.02\times 10^{23} molecules is equal 1 mole of Na_{3}C_{6}H_{5}O_{7} if produced then 3 moles of NaHCO_{3} is required, which is not given in the option. So it is wrong.

d) 54 g of water or 3 moles of H_{2}O (<em>Molecular Weight of water is 18 g</em>) is produced when 3 moles of NaHCO_{3} is used but in this option only one mole of NaHCO_{3} is given. So it is wrong.

8 0
2 years ago
Read 2 more answers
PLEASE HELP!!!!!
Doss [256]
A) an acid because it turns the paper blue
6 0
2 years ago
In order to reduce the exposure to organic solvents like turpentine, some art instructors recommend the students clean brushes a
kykrilka [37]
Generally speaking, organic molecules tend to dissolve in solvents that have similar physical properties. A good rule of thumb is that "like dissolves like". Meaning, polar compounds can dissolve polar compounds and nonpolar compounds can dissolve nonpolar compounds.

To apply this to the current problem, we are told that the brushes are being cleaned with vegetable oil or mineral oil. In this case, the oils are used as solvents. In order for these solvents to be effective, the compounds they are trying to dissolve must be similar in structure and properties to other oils. Therefore, vegetable oil or mineral oil will be most effective in removing oil-based paints, as these will have the similar properties needed to dissolve in the oil solvents.
6 0
2 years ago
Which best describes the relationships between subatomic particles in any neutral atom? * 1 point the number of electrons equals
Anna71 [15]

Atomic number = protons

Protons = P  Electrons = E     P = E

Atomic mass = Neutrons + Protons

Atomic number = atomic mass = neutrons

P = E

AM - AN = N

Example:

Calcium = 20 Protons  20P = 20E

Atomic mass - atomic number = neutrons :)

4 0
2 years ago
Anyway, which is a spectator ion involved in the reaction of k2cro4(aq) and ba(no3)2(aq)?
marissa [1.9K]

Nitrate ions \text{NO}_3^{-} and potassium ions \text{K}^{+}.

<h3>Explanation</h3>

Potassium dichromate undergoes a double-decomposition reaction with barium nitrate to produce barium dichromate and potassium nitrate. The reaction is possible due to the low solubility of barium dichromate that precipitate out of the solution readily after its production.

Start with the balanced chemical equation for this process:

\text{K}_2\text{CrO}_4 \; (aq) + \text{Ba}(\text{NO}_3)_2 \; (aq) \to \text{Ba}(\text{CrO}_4)_2 \; (s) + 2 \; \text{KNO}_3 \; (aq)

Rewrite the chemical equation as an ionic one; express all soluble salts- those with state symbol (aq)- as their constituting ions while leaving the insoluble (s) intact.

2 \; \text{K}^{+}\; (aq)+ 2\; \text{CrO}_4^{-} \; (aq) + \text{Ba}^{2+} \; (aq) + 2 \; \text{NO}_3^{-} \; (aq) \\ \to \text{Ba}(\text{CrO}_4)_2 \; (s) + 2 \; \text{K}^{+} \; (aq) + 2 \; \text{NO}_3^{-} \; (aq)

\text{K}^{+} and \text{CrO}_4^{-} are found on both sides of the equation by the same quantity. The two ions thus took no part in the net reaction and act as spectator ions.

5 0
2 years ago
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