I would say, "not those kinds of kernels, when I say kernel, I mean the core of your computers operating system. It controls all of the system components and tell specific parts of the computer to do certain things." or in more compact terms, "think of the kernel as the brain of the computer, telling each system component what to do."
I am guessing. My guess is code.
Answer:
Option (B) is the correct of this question.
Explanation:
The performance of a monitor and process counters to observe the performance is the tool or method which determines the new software is hogging the computer resources. So this way the user don't have any problem with computer.
- You can view log files in Windows Performance Monitor to see a visual representation of the performance counter data.
- Performance counters are bits of code that log, count, and measure software events that allow a high-level view of user trends.
- To customize the tracking of AD FS output using the Quality Monitor.
- Type Output Monitor on Start screen, then click ENTER.
- Expand Data Collector Sets in the console tree, right-click on User Specified, point to New, then select Data Collector Collection.
Other options are incorrect according to the given scenario.
Answer:
Explanation:
temporal locality can be defined as: when a particular memory is referenced or accessed several times within a specific period of time. In the question, i think the variable that exhibit temporal locality are I, J and 0(all the variable). This is because the variable J and 0 are accessed several times within the loop. I would not have been part of it, but in the A[I][J]=B[I][0]+A[J][I], the variable "I" is also accessed in the addition. this is why it is part of the temporal locality.
Answer with Explanation:
An I/O-bound the programs that are used relatively a little processor times and are favored by an algorithm. However, if the processor bound process is denied the processor time for the sufficiently long periods of times, the same algorithms will be granted a processor to the process and it has not use the processors at all in recent pasts. Therefore, the processor bound process will not be the permanently denied to access.