What’s the formula for the sequence 13,27,41,55,....

Two wires with lengths of 448 cm and 616 cm are to be cut into pieces of all the same length without a remainder. Find the great

Y_Kistochka [10]

Answer:

56 cm

Step-by-step explanation:

We need ro find the GCD of these numbers. In finding the GCD, we list the multiples of the number, beginning with the smallest number. Here, the

The factors of 616=2*2*2*7*11

The factors of 448 =2*2*2*2*2*2*7

Common factors in both are 2*2*2*7=56

Therefore, the greatest possible length is 56 cm

6 0

2 years ago

Susan keeps track of the number of tickets sold for each play presented at the community theater. within how many standard devia

Citrus2011 [14]

The Mean = (135 + 71 + 69 + 80 + 158 + 152 + 161 + 96 + 122 + 118 + 87 + 85 ) : 12 = 111.166
The smallest value : 69
The greatest value : 161
s² = ∑( x i - x )² / ( n - 1 )
s² = ( 568.274 + 1613.3 + 1777.97 + 971.32 + 2193.42 + 1667.4 + +2483.42 + 230 + 117.38 + 46.7 + 584 + 684.66 ) : 11
s² = 1176.1676
s = √s² = √1176.1676
s ( Standard deviation ) = 34.295
All the values fall within 2 standard deviations:
x (Mean) - 2 s and x + 2 s

3 0

2 years ago

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A publisher needs to send many books to a local book retailer and will send the books in a combination of small and large boxes.

PSYCHO15rus [73]

Answer:

4 large boxes and 2 small boxes

Step-by-step explanation:

4 X 55 =220 books

2 X 30 = 60 books

Total = 280 books

6 0

2 years ago

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Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. Scores o

otez555 [7]

Answer:

Due to the higher z-score, David has the higher standardized score

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Which student has the higher standardized score

Whoever had the higher z-score.

David:

Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. So $X = 52, \mu = 70, \sigma = 11$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{52 - 70}{11}$

$Z = -1.64$

Steven:

Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 6. Steven has a score of 52 on Ms. So $X = 52, \mu = 64, \sigma = 6$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{52 - 64}{6}$

$Z = -2$

Due to the higher z-score, David has the higher standardized score

3 0

2 years ago

Approximate the area under the curve y = x² from x = 2 to x = 5 using a Right Endpoint approximation with 6 subdivisions.

Tanzania [10]

Answer:

$\text{Area}\,=36.75$

Step-by-step explanation:

Using right estimation point simply means to form a bunch of rectangles between the two limits, x =2 and x = 5. and add the areas of all those rectangles.

There must be 6 subdivisions between 2 and 5. so, to do that:

$\Delta{x}=\dfrac{5-2}{6}=0.5$

the length of each subdivision is 0.5 units. That also means that the 6 rectangles in between the limits will each have the base length of 0.5 units.

So the endpoints of each subdivision from 3 to 5 will be:

$\begin{tabular}{|c|c|c|c|c|}3&3.5&4&4.5&5\\\end{tabular}$

By <em>right </em>endpoint approx<em>, </em>we mean that the height of the rectangles will be determined by the right endpoint of each subdivision, that is, it must be equal to the function value of the first limit.

$\begin{tabular}{|c|c|c|}subdivision&$x$&height($y=x^2$)&3 to 3.5&3.5&12.25&3.5 to 4&4&16&4 to 4.5&4.5&20.25&4.5 to 5&5&25\end$

Note that we have used the right-end-point of the subdivision to determine the height the rectangles.

All that's left to do now is to simply calculate the areas of the each of the rectangles. And add them up.

the base of each of the rectangle is $\Delta{x}=0.5$

and the height is determined in the table above.

$\text{Area}\,=(0.5\times12.25)+(0.5\times16)+(0.5\times20.25)+(0.5\times25)$

$\text{Area}\,=0.5(12.25+16+20.25+25)$

$\text{Area}\,=36.75$

3 0

2 years ago