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Usimov [2.4K]
2 years ago
6

A sand dune stands 5 feet above sea level. The hill is eroding at a rate of 1 foot per 20 years. Let y represent the height of t

he sand dune after x years. Which equation represents the situation? y = negative StartFraction 1 Over 20 EndFraction x minus 5 y = negative StartFraction 1 Over 20 EndFraction x + 5 y = negative 20 x minus 5 y = negative 20 x + 5
Mathematics
2 answers:
sergejj [24]2 years ago
8 0

Answer:

y = 1/20 x + 5

Step-by-step explanation:

Let the height of the sand dune after x years be represented by the equation

y = mx+c where;

m is the rate at which the hills is eroding

c is the height of the dunes above the sea

If The hill is eroding at a rate of 1 foot per 20 years,then the rate of eroding per year will be;

1foot = 20years

m = 1year

Cross multiply

20m = 1

m = 1/20 foot/yr...

c = 5foot

Substitute into the formula:

y = 1/20 x + 5

Hence the equation that represent the situation is y = 1/20 x + 5

Lilit [14]2 years ago
5 0

Answer:y = 1/20 x + 5

Step-by-step explanation:

Let the height of the sand dune after x years be represented by the equation

y = mx+c where;

m is the rate at which the hills is eroding

c is the height of the dunes above the sea

If The hill is eroding at a rate of 1 foot per 20 years,then the rate of eroding per year will be;

1foot = 20years

m = 1year

Cross multiply

20m = 1

m = 1/20 foot/yr...

c = 5foot

Substitute into the formula:

y = 1/20 x + 5

Hence the equation that represent the situation is y = 1/20 x + 5

Step-by-step explanation:

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Given:

Amount in the bank account = $1850

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When would automatic payments make the value of the account zero?

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On dividing the amount by monthly payment, we get

\dfrac{1850}{400.73}=4.61657

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Rewrite the expression (3a^2b^3c^5)/(8x^4y^3z)so that it has no denominator. (note: do not use a fraction line in your answer. a
Gemiola [76]
Use:

\dfrac{1}{a}=a^{-1}\\\\\dfrac{1}{a^n}=a^{-n}

\dfrac{3a^2b^3c^5}{8x^4y^3z}=3a^2b^3c^5\cdot8^{-1}x^{-4}y^{-3}z^{-1}

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1 year ago
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A triangle ABC is inscribed in a circle, such that AB is a diameter. What are the measures of angles of this triangle if: measur
shutvik [7]

Answer:

The measures of angles of this Δ are 23° , 67° , 90°

Step-by-step explanation:

* Lets talk about some facts in the circle

- An inscribed angle is an angle made from points sitting on the

 circle's circumference

- A central angle is the angle formed when the vertex is at the center

 of the circle

- The measure of an arc of a circle is equal to the measure of the

 central angle that intercepts the arc.

- The measure of an inscribed angle is equal to 1/2 the measure of

 its intercepted arc

- An angle inscribed across a circle's diameter is always a right angle

- The triangle is inscribed in a circle if their vertices lie on the

  circumference of the circle, and their angles will be inscribed

  angles in the circle

* Now lets solve the problem

- Δ ABC is inscribed in a circle

∵ its side AB is a diameter of the circle

∵ Its vertex C is on the circle

∴ ∠C is inscribed and across the circle's diameter

∴ ∠C is a right angle

∴ m∠C = 90°

∵ The measure of arc BC = 134°

∵ ∠A is inscribed angle subtended by arc BC

∵ The measure of an inscribed angle is equal to 1/2 the measure

   of its intercepted arc

∴ m∠A = 1/2 × 134° = 67°

∵ The sum of the measures of the interior angles of a triangle is 180°

∵ m∠A = 67°

∵ m∠C = 67°

∵ m∠A + m∠B + m∠C = 180°

∴ 67° + m∠B + 90° = 180°

∴ 157° + m∠B = 180° ⇒ subtract 157 from both sides

∴ m∠B = 23°

* The measures of angles of this Δ are 23° , 67° , 90°

4 0
1 year ago
Evaluate the expression. P(9, 3) · P(5, 4)
boyakko [2]

Answer:

P(9,3) *P(5,4)

And if we use the permutation formula given by:

nPx = \frac{n!}{(n-x)!}

And replacing we got:

\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520

Step-by-step explanation:

For this problem we want to find the following expressionÑ

P(9,3) *P(5,4)

And if we use the permutation formula given by:

nPx = \frac{n!}{(n-x)!}

And replacing we got:

\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520

6 0
2 years ago
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