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2 years ago

What it the oxidation number for bromine in the molecule H2Br2O6?

Chemistry

1 answer:

mafiozo [28]2 years ago

6 0

Answer:

ok i figured it out for real this time. the answer is positive 5

Explanation:

i asked my teacher

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Match each term to a correct example from the chemical equation: 2A + B2 → 2AB.

kari74 [83]

Explanation:

The given equation is as follows.

$2A + B_{2} \rightarrow 2AB$

Reactants are the species present on the left hand side of a chemical equation.

Products are the species present on the right hand side of a chemical equation.

Whereas coefficients are the number present in front of formulas.

Therefore, in the given reaction equation, matched terms are as follows.

Reactant is $B_{2}$
Product is AB.
Coefficient is 2.

3 0

2 years ago

Which statements about reducing sugars are true? D‑Glucose (an aldose) is a reducing sugar. The oxidation of a reducing sugar fo

qaws [65]

Answer:

The true statements are given below.

Explanation:

1 D glucose is a reducing sugar

2 The oxidation of reducing sugar forms a carboxylic acid sugar.

D glucose is a reducing sugar because glucose contain a free hydroxyl group (-OH)in its anomeric carbon.

The oxidation of reducing sugar result in the conversion of -CHO group in case of aldose sugar and -CH2OH group in case of ketose sugar into carboxylic acid(-COOH).

4 0

2 years ago

How many carbon atoms are contained in 2.8 g of c2h4 ?

MrRa [10]

Answer:

The answer to your question is: 1.205 x 10²³ atoms of Carbon

Explanation:

Data

Carbons atoms contained in 2.8 g C₂ H₄

MW C₂ H₄ = (12 x 2) + (4 x 1) = 24 + 4 = 28 g

28 g of C₂ H₄ ---------------- 24 g of carbon

2.8 g C₂ H₄ ----------------- x

x = (2.8)(24) / (28)

= 2.4 grams of C

1 mol ------------------- 12 g of Carbon

x ------------------- 2.4 g

x = (2.4x 1) / 12 = 0.2 mol

1 mol ----------------- 6.023 x 10 ²³ atoms

0.2 mol -------------- x

x = (0.2 x 6.023 x 10 ²³) / 1

= 1.205 x 10²³ atoms

8 0

2 years ago

Read 2 more answers

How many moles of copper are in 6,000,000 atoms of copper?

crimeas [40]

Answer: There will be 9.9632 × 10⁻¹⁸ moles of Copper in 6,000,000 atoms of Copper.

7 0

1 year ago

What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom

Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains $6.022\times 10^{23}$ atoms

So, 5.5 g of lead contains $\frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22}$ atoms

and,

As, 118.71 g of lead contains $6.022\times 10^{23}$ atoms

So, 94.5 g of lead contains $\frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23}$ atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

$\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%$

and,

$\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%$

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

6 0

2 years ago