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liberstina [14]
2 years ago
5

A shield of material that reflects neutrons is placed around a radioactive sample.

Physics
2 answers:
Tanya [424]2 years ago
4 0
<h3><u>Answer;</u></h3>

A) A chain reaction will be sustained in a sub-critical mass

<h3><u>Explanation</u>;</h3>
  • Critical mass is the minimum or the smallest amount of a given fissile material necessary to achieve a self-sustaining fission chain reaction under stated conditions.
  • A subcritical mass is a mass of fissile material that does not have the ability to sustain a fission chain reaction.
nikitadnepr [17]2 years ago
3 0
The answer is A. just took the test
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A box slides down a frictionless plane inclined at an angle θ ¸ above the horizontal. The gravitational force on the box is dire
DedPeter [7]
<h2>Answer: at an angle \theta below the inclined plane. </h2>

If we draw the <u>Free Body Diagram</u> for this situation (figure attached), taking into account only the gravity force in this case, we will see the weight W of the block, which is directly proportional to the gravity acceleration g:  

W=m.g

This force is directed vertically at an angle \theta below the inclined plane, this means it has an X-component and a Y-component:

W=W_{X}+W_{Y}

W_{X}=m.g.cos(\theta)

W_{Y}=m.g.sin(\theta)

Therefore the correct option is c

6 0
2 years ago
Read 2 more answers
A steel rod with a length of l = 1.55 m and a cross section of A = 4.45 cm2 is held fixed at the end points of the rod. What is
Blababa [14]

To solve this problem it is necessary to apply the concepts related to thermal stress. Said stress is defined as the amount of deformation caused by the change in temperature, based on the parameters of the coefficient of thermal expansion of the material, Young's module and the Area or area of the area.

F = AY\alpha \Delta T

Where

A = Cross-sectional Area

Y = Young's modulus

\alpha= Coefficient of linear expansion for steel

\Delta T= Temperature Raise

Our values are given as,

A = 4.45cm^2

T = 37K

\alpha = 1.17*10^{-5}K^{-1}

Y = 200*10^9Gpa

Replacing we have,

F = (4.45*10^{-4})(200*10^9)(1.17*10^{-5})(37)

F = 38526.1N

Therefore the size of the force developing inside the steel rod when its temperature is raised by 37K is 38526.1N

7 0
2 years ago
What units are given to the right of the equals sign
zhuklara [117]
The answer

2y + 14 = 17

The 17 is to the right of the = sign
It is also the answer
7 0
2 years ago
Fred wants to summarize mitosis in the cell cycle. Which statement describes mitosis?
salantis [7]
The statement that most accurately describes mitosis simply is <span>that mitosis is a type of cell division in which one cell (the mother) divides to produce two new cells (the daughters) that are genetically identical to itself</span>. This is the most basic textbook definition, that is summary, of what the mitosis is.
6 0
2 years ago
Read 2 more answers
Many industries are powered via distant power stations. Calculate the current flowing through a 7,300m long 10. copper power lin
Oliga [24]

Answer:

Current, I = 1000 A

Explanation:

It is given that,

Length of the copper wire, l = 7300 m

Resistance of copper line, R = 10 ohms

Magnetic field, B = 0.1 T

\mu_o=4\pi \times 10^{-7}\ T-m/A

Resistivity, \rho=1.72\times 10^{-8}\ \Omega-m

We need to find the current flowing the copper wire. Firstly, we need to find the radius of he power line using physical dimensions as :

R=\rho \dfrac{l}{A}

R=\rho \dfrac{l}{\pi r^2}

r=\sqrt{\dfrac{\rho l}{R\pi}}

r=\sqrt{\dfrac{1.72\times 10^{-8}\times 7300}{10\pi}}

r = 0.00199 m

or

r=1.99\times 10^{-3}\ m=2\times 10^{-3}\ m

The magnetic field on a current carrying wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

I=\dfrac{2\pi rB}{\mu_o}

I=\dfrac{2\pi \times 0.1\times 2\times 10^{-3}}{4\pi \times 10^{-7}}

I = 1000 A

So, the current of 1000 A is flowing through the copper wire. Hence, this is the required solution.

4 0
2 years ago
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