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2 years ago

A car moving 12 m/s stops in 3 seconds vf=

Physics

2 answers:

Alla [95]2 years ago

4 0

Your question is not complete
For this I can answer only this
That it can stop in 3 seconds

allsm [11]2 years ago

4 0

Answer:

The question seems to be looking for vf, which may be the final velocity.

We know that the car stops, so the car is at rest, this means that the final velocity is equal to zero.

vf = 0 m/s

Now, we also can find the acceleration, the velocity equation can be written as:

v(t) = a*t + 12m/s

We know that in 3 seconds the car stops, so we have:

v(3s) = 0 = a*3s + 12m/s

a= -12m/s*(1/3s) = -4m/s^2

So in those 3 seconds where the car is stoping, the acceleration of the car is -4m/s^2, and the velocity of the car in those 3 seconds can be described by the equation:

v(t) = -4m/s^2*t + 12m/s

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e-lub [12.9K]

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2 years ago

A boy on a bicycle approaches a brick wall as he sounds his horn at a frequency 400 hz. the sound he hears reflected back from t

Mashutka [201]

As the question is about changing in frequency of a wave for an observer who is moving relative to the wave source, the concept that should come to our minds is "Doppler's effect."

Now the general formula of the Doppler's effect is:
$f = (\frac{g + v_{r}}{g + v_{s}})f_{o}$ -- (A)

Note: We do not need to worry about the signs, as everything is moving towards each other. If something/somebody were moving away, we would have the negative sign. However, in this problem it is not the issue.

Where,
g = Speed of sound = 340m/s.
$v_{r}$ = Velocity of the receiver/observer relative to the medium = ?.
$v_{s}$ = Velocity of the source with respect to medium = 0 m/s.
$f_{o}$ = Frequency emitted from source = 400 Hz.
$f$ = Observed frequency = 408Hz.

Plug-in the above values in the equation (A), you would get:

$408 = ( \frac{340 + v_{r}}{340 + 0})*400$

$\frac{408}{400} = \frac{340 + v_{r}}{340}$

Solving above would give you,
$v_{r}$ = 6.8 m/s

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2 years ago

A block is projected with speed v across a horizontal surface and slides to a stop due to friction. The same block is then proje

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Explanation:

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From the information given, it should be known that when the block is projected with the same speed v up an incline where is slides to a stop due to friction, the box will lose its kinetic energy but there'll be na increase in the potential energy as a result of the veritcal height. This then brings about an increase in the mechanical energy.

Therefore, the total mechanical energy of the block will decrease the least when the case on the inclined surface had the least decrease intotal mechanical energy.

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1 year ago