(a) Data with the eight day's measurement.
Raw data: [60,58,64,64,68,50,57,82],
Sorted data: [50,57,58,60,64,64,68,82]
Sample size = 8 (even)
mean = 62.875
median = (60+64)/2 = 62
1st quartile = (57+58)/2 = 57.5
3rd quartile = (64+68)/2 = 66
IQR = 66 - 57.5 = 8.5
(b) Data without the eight day's measurement.
Raw data: [60,58,64,64,68,50,57]
Sorted data: [50,57,58,60,64,64,68]
Sample size = 7 (odd)
mean = 60.143
median = 60
1st quartile = 57
3rd quartile = 64
IQR = 64 -57 = 7
Answers:
1. The average is the same with or without the 8th day's data. FALSE
2. The median is the same with or without the 8th day's data. FALSE
3. The IQR decreases when the 8th day is included. FALSE
4. The IQR increases when the 8th day is included. TRUE
5. The median is higher when the 8th day is included. TRUE
Answer:
x= -1/3
Step-by-step explanation:
2x+7x=-3
9x/9= -3/9
x = -1/3
To find out d answer to dis we need to subtract d amount of plastic trains by d amount of wooden trains. d answer will be d answer to your question. lets do it:-
41 - 23 = 18
Jimmy sees 18 more plastic trains than wooden trains.
CHECK OUR WORK:-
18 + 23 = 41
We were RIGHT!!
So, Jimmy sees 18 more plastic trains than wooden trains.
Hope I helped ya!! xD
The domain would be x ≥ 0.
This is because the outlet cannot have profit before it was open. Therefore, the growth must be from year 0 to present. If they give a year as starting, you can have an upper limit too, but there is not enough information here to determine that information.