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scoundrel [369]

2 years ago

10

You and your friend play a trivia game. You answer 64% of the questions correctly and your friend answers 0.74 of the questions

correctly. What is the minimum number of questions in the game?

2 answers:

pychu [463]2 years ago

6 0

Answer:

higher then 64

Step-by-step explanation:

OLga [1]2 years ago

5 0

Answer:

higher then 64

Step-by-step explanation:

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Reyna has 5 coins worth 10 cents each and 4 coins

Zolol [24]

Answer:

The Probability found is:

P = $\frac{13}{18}$

Step-by-step explanation:

Let x be the 10 cents coin.

Let y be the 25 cents coin.

We have to find all the possible outcomes

1) First coin = 10 cents, Second coin = 10 cents , so

(x,x) = 20

2) First coin = 10 cents, Second coin = 25 cents , so

(x,y) = 35

3) First coin = 25 cents, Second coin = 10 cents , so

(y,x) = 35

4) First coin = 25 cents, Second coin = 25 cents , so

(y,y) = 50

Find the probability of each outcome:

P(x,x) = $\frac{5}{9}\cdot\frac{4}{8}=\frac{20}{72}$

P(x,y) = $\frac{5}{9}\cdot\frac{4}{8}=\frac{20}{72}$

P(y,x) = $\frac{5}{9}\cdot\frac{4}{8}=\frac{20}{72}$

P(y,y) = $\frac{4}{9}\cdot\frac{3}{8}=\frac{12}{72}$

Add all the probabilities where sum is at least 35 i.e P(x,y) , P(y,x) , P(y,y)

P(x,y) + P(y,x) + P(y,y) = $\frac{20}{72}+\frac{20}{72}+\frac{12}{72} = \frac{52}{72}=\frac{13}{18}\\$

6 0

2 years ago

On any given day, Juan will break even if he earns as much money as he spends. On day 5, he records the expression 16+ (-16). Do

sertanlavr [38]

Answer:

Yes. Juan will break even because 16 and -16 are a zero pair. -16 is the additive inverse of 16. So the sum will be 0.

6 0

2 years ago

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Vector bought 15.6 pounds of paintballs. all together, the balls cost 35.99. About how much dis the psinballs cost per pond?

nevsk [136]

Paintballs are $2.30 per pound.

6 0

2 years ago

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A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a random

Harlamova29_29 [7]

Answer with explanation:

Given : Sample mean = $\overline{x}=\text{48.47 pounds}$

Standard deviation : $\sigma=\text{ 3.1 pounds.}$

Sample size : n = 36

Claim : $\mu\neq50$

∴ $H_0:\mu=50$

$H_1:\mu\neq50$

Since the alternative hypothesis is two tail , then the test is two tail test.

By using a z statistic and a 0.05 level of significance. Reject $H_0$ if z < -1.960 or is z> 1.960.

Then , the test static for population mean is given by :-

$z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

$z=\dfrac{48.47-50}{\dfrac{3.1}{\sqrt{36}}}\approx-2.96$

We reject $H_0$ since $-2.96\leq -1.96$ . We have statistically significant evidence at $\alpha=0.05$ to show that the mean amount of garbage per bin is not different from 50.

5 0

2 years ago

What is the approximate volume of a cone with a height of 12 in. and radius of 9 in.?

swat32

The answer would be 1017.88 in³. Use the volume for cones ( 1/3 times pi times radius times height) so 1/3*3.14*9*12 in which would be 1017.88 in³ hope it helps!

4 0

2 years ago

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