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Anvisha [2.4K]
2 years ago
6

Simon leaves home at 10:30am. He has return home before 6:15pm. He has to travel to work, which takes 45 minutes; he is working

a four hour shift. He wants to meet some friends after work. His journey to his friends is 10 minutes and his return journey home is 42 minutes. What is the maximum amount of time he can spend with his friends?
Mathematics
1 answer:
lakkis [162]2 years ago
4 0

Answer:

2 hours and 18 minutes

Step-by-step explanation:

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baker has 5\dfrac145 4 1 ​ 5, start fraction, 1, divided by, 4, end fraction pies in her shop. She cut the pies in pieces that a
kupik [55]

Answer:

The answer is "She cut a total of 42 pieces of pie".

Step-by-step explanation:

Given :

Total pie=  5 \frac{1}{4}

cut pie = \frac{1}{8}

The number of pieces of the pie she has=?

Solve the mixed fraction value:

\to 5 \frac{1}{4}= \frac{21}{4}

If she cuts the pieces into the entire pie, that is  = \frac{1}{8}  

So, the equation is:

\to \frac{21}{4} = \frac{1}{8} \times x

\to x= \frac{21 \times 8}{4}\\\\ \to x= 21 \times 2\\\\ \to  x=42

7 0
2 years ago
The value of a gold coin picturing the head of the Roman Emperor Vespasian is increasing at the rate of 5% per year. If the coin
bazaltina [42]

Answer:

255.75

Step-by-step explanation:

6 0
2 years ago
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It is known that driving can be difficult in regions where winter conditions involve snow-covered roads. For cars equipped with
noname [10]

Answer:

The null and alternative hypothesis for this test are

H_0: \mu\ge 215\\\\H_1: \mu< 215

Step-by-step explanation:

If we perform a hypothesis test, we can reject or not reject the null hypothesis.

To conclude that the tires have a decreased stopping distance (μ<215), we should state the null hypothesis H_0: \mu\ge 215 and then go on with the analysis to reject it (or not).

If the null hypothesis is rejected, the claim of the manufacturer is rigth.

The alternative hypothesis would be H_1: \mu, that would turn rigth if the null hypothesis is rejected.

5 0
2 years ago
Define four symbolic constants that represent integer 25 in decimal, binary, octal, and hexadecimal formats
stealth61 [152]

Answer:

1) Decimal    25= (25)_{10}

2) Binary    25= (11001)_2

3) Octal   25= (31)_8

4) Hexadecimal   25= (19)_{16}

Step-by-step explanation:

Given : Integer is 25                      

To find : Represent integer in decimal, binary, octal, and hexadecimal formats.

Solution :

1) Integer into decimal - To convert into decimal the base goes to 10.

So, 25= (25)_{10}

2) Integer into binary - To convert into binary the base goes to 2, it form in 0 and 1 and we divide integer by 2.

Divide 25 by 2 and note down the remainders.

2 | 25

2 | 12    R=1    ←

2 | 6     R=0   ↑

2 | 3      R=0  ↑

2 | 1  →   R=1   ↑

So,   25= (11001)_2

3) Integer into octal - To convert into octal the base goes to 8 and we divide integer by 8.

Divide 25 by 8 and note down the remainders.

8 | 25

  | 3 →   R=1    

So,   25= (31)_8

4) Integer into hexadecimal - To convert into hexadecimal the base goes to 16 and we divide integer by 16.

Divide 25 by 16 and note down the remainders.

16 | 25

   | 1 →   R=9    

So,   25= (19)_{16}

3 0
2 years ago
Consider a disease whose presence can be identified by carrying out a blood test. Let p denote the probability that a randomly s
kifflom [539]

Answer:

The expected number of tests, E(X) = 6.00

Step-by-step explanation:

Let us denote the number of tests required by X.

In the case of 5 individuals, the possible value of x are 1, if no one has the disease, and 6, if at least one person has the disease.

To find the probability that no one has the disease, we will consider the fact that the selection is independent. Thus, only one test is necessary.

Case 1: P(X=1) = [P (not infected)]⁵

                       = (0.15 - 0.1)⁵

            P(X=1) = 3.125*10⁻⁷

Case 2: P(X=6) = 1- P(X=1)

                        = 1 - (1 - 0.1)⁵

               P(X=6) = (1 - 3.125*10⁻⁷) = 0.999999

               P(X=6) = 1.0

We can then use the previously determined values to compute the expected number of tests.

E(X) = ∑x.P(X=x)

      = (1).(3.125*10⁻⁷) + 6.(1.0)

 E(X)  =  E(X) = 6.00

Therefore, the expected number of tests, E(X) = 6.00

3 0
2 years ago
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