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1 year ago

The diagonals of kite ABCD intersect at E. If ∡EBC=30°, what is ∡BCE?

Mathematics

1 answer:

lukranit [14]1 year ago

8 0

Answer:

∡BCE = 60

Step-by-step explanation:

Here, we want to find the angle marked BCE

From our diagram, the angle marked BCE is y

Looking at triangle BCE, we have the right angle, an angle measure of 30 and the angle marked y which we say is BCE

mathematically, the sum of all these will give 180 as the sum f the interior angles of a triangle is 180

Thus, we have that;

y + 30 + 90 = 180

y = 180-120

y = 60

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Solve (Y+5)^3/2=4 where y is a real number

koban [17]

Answer:

$y {}^{2} + 10y = - 33.5$

Step-by-step explanation:

(y+5)(y+5)x3/2=4

Y(y+5)+5(y+5) x 3/2=4

$y {}^{2} + 5y + 5y + 25 \times 3 \2 = 4$

$y ^{2} + 10y + 75 \2 = 4$

$y {}^{2} + 10y + 37.5 = 4$

$y {}^{2} + 10y = 4 - 37.5$

$y {}^{2} + 10y = - 33.5$

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1 year ago

Emma has completed 70% of her summer reading list. She has read 14 books so far. How many books are there on her summer reading

REY [17]

The number of books in her summer reading list is = 20

The number of books that has been read by Emma = 14

The percentage of books that has been read by Emma = 70%

But the percentage of books in Emma summer reading list = 100%

∴ The number of books in her reading list= ˣ

That is ;

70% = 14

100% = ˣ

Make ˣ the subject of formula,

ˣ = 100 × 14 / 70

ˣ = 20

Learn more here:

brainly.com/question/20766171

7 0

2 years ago

A sample of tritium-3 decayed to 94.5% of its original amount after a year.

Zolol [24]

(a) If $y(t)$ is the mass after $t$ days and $y(0) = A$ then $y(t) = Ae^{kt}.$

$y(1) = Ae^k = 0.945A \implies e^k = 0.945 \implies k = \ln 0.945$

$\text{Then } Ae^{(\ln 0.945)t} = \frac{1}{2}A\ \Leftrightarrow\ \ln e^{(\ln 0.945)t} = \ln \frac{1}{2}\ \Leftrightarrow\ ( \ln 0.945) t = \ln \frac{1}{2} \Leftrightarrow \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 12.25 \text{ years}$

(b)
$Ae^{(\ln 0.945) t} = 0.20 A \ \Leftrightarrow\ (\ln 0.945) t \ln \frac{1}{5}\ \implies \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 28.45\text{ years}$

3 0

2 years ago

A 20-person fraternity is making their weekend plans around 5 different parties in IV. Each brother will attend exactly one of t

skad [1K]

Answer:

3876

Step-by-step explanation:

Given the following :

Fraternity members = 20

They are to attend 5 different parties in groups of 4

Meaning a group = 4 persons

Atleast one brother will attend exactly one of the parties. (the brothers are indistinguishable).

Then, exactly one brother at a party (20 - 1) = 19, since they are indistinguishable.

Group members are in 4's

19C4

From: nCr = n! /(n-r)! r!

19C4 = 19! / (19 - 4)! 4!

= 19! / 15! 4!

= (19 * 18 * 17 * 16) / (4 * 3 * 2)

= 93024 / 24

= 3876

3 0

2 years ago

Find the value of x, & y.<br> 3x-y+8x-7=x+2y+5x+3y

Advocard [28]

Please rewrite this equation(s) using parantheses than needed

thank you

5 0

2 years ago