Answer:
92 ATP
Explanation:
Fatty acid oxidation results in the formation of large number of ATP molecules. Three important process of fatty acid are activation of the fatty acid, beta oxidation and entry of acetyl CoA in Krebs cycle.
14 carbon fatty acid is Miristic acid. The complete oxidation of Miristic acid results in the formation of 7 acetyl CoA + 6NADH and 
1 Acetyl CoA gives 10 molecules of ATP then 7 acetyl CoA gives 70 molecules of ATP.
1NADH = 2.5 ATP, 6NADH = 15 ATP.
= 1.5 ATP,
= 9 ATP.
2 ATP has been consumed in the activation of fatty acid.
Total ATP = 70+15+9-2
=92 ATP.
Thus, the total ATP generated from the oxidation of 14 carbon fatty acid is 92.
The compound that could serve as a reactant in the neutralization reaction is H2SO4
Explanation
Neutralization reaction occur between an acids and a base. H2SO4 ( sulfuric acid) is a strong acid. It can be neutralized by strong base such as NaOH ( sodium hydroxide)
Example of neutralization reaction is
2NaOH + H2SO4 → Na2SO4 + 2H2O
Answer:
It is a crystalline solid.
It is a white crystalline solid that is practically insoluble in water, soluble in diethyl ether and slightly soluble in ethanol
Explanation:
The difference between crystalline and amorphous is how this chemical compound transmits light.
When a chemical material or compound is said to be crystalline, it is the opposite of what we imagine, since its color is opaque and does not allow light to pass through it, that is why this compound, being crystalline, is opaque white. and if you want to see through it you will not see the other way since it is not "transparent".
On the other hand, amorphous chemical materials or compounds are seen through them from one side to the other, they are considered "transparent" and do not refract any color from the color range of light. That is why they are not opaque either, nor do they have a particular color like white. A clear example of an amorphous structure is glass or crystal.
Answer:
104.84 moles
Explanation:
Given data:
Moles of Boron produced = ?
Mass of B₂O₃ = 3650 g
Solution:
Chemical equation:
6K + B₂O₃ → 3K₂O + 2B
Number of moles of B₂O₃:
Number of moles = mass/ molar mass
Number of moles = 3650 g/ 69.63 g/mol
Number of moles = 52.42 mol
Now we will compare the moles of B₂O₃ with B from balance chemical equation:
B₂O₃ : B
1 : 2
52.42 : 2×52.42 = 104.84
Thus from 3650 g of B₂O₃ 104.84 moles of boron will produced.