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kaheart [24]
2 years ago
9

Choose the expression that uses the GCF and the Distributive property to find 66 + 24 + 78.

Mathematics
2 answers:
Alexxx [7]2 years ago
5 0

Answer:

112

Step-by-step explanation:

Serggg [28]2 years ago
5 0

Answer: 6

Step-by-step explanation:

The greatest common factor is 6.

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Nam owns a used car lot. He checked the odometers of the cars and recorded how far they had driven. He
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Answer:

a histogram

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You can count easily from hiistogram how many vehicles had driven more than 200,000 km (kilometers) and that's not the case with the box plot

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99×101 has the same value as (99×100)+1 (99×100)-(99×1) (99×100)+(99×1) (99×100)(99×1)
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99 * 101=

99 * (100+1)

= 99 * 100 + 99*1

(99×100)+(99×1)


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Using the exchange rate £1 = $1.33, calculate how many £ are in $6.50. Give your answer rounded to 2 dp.
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Answer:

Step-by-step explanation:

If the exchange rate between British pounds (£) and US dollars ($) is £1 = $1.40, how much is £200 worth in dollars?

Include the $ sign in your answer.

280

$142.86

280.00

$280.00

$280

42.86

6 0
2 years ago
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Congratulations you received a score of 3.4 on your annual review . Merit increases are given out starting at .5% at a score of
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<span>Using the formula above, your merit increase will be 2.5%. You received a score of 3.4 on your annual review. Since the merit increase model is 0.5% salary increase at a score of 2.6, with an additional 1% for every .4 points above that baseline, you get 2.5%, which is the baseline of 0.5% + 2% for the 0.8 points you scored above that baseline.</span>
6 0
2 years ago
A psychologist is collecting data on the time it takes to learn a certain task. For 50 randomly selected adult subjects, the sam
tatuchka [14]

Answer: (15.263,\ 17.537)

Step-by-step explanation:

According to the given information, we have

Sample size : n= 50

\overline{x}=16.40

s=4.00

Since population standard deviation is unknown, so we use t-test.

Critical value for  95 percent confidence interval  :

t_{n-1,\alpha/2}=t_{49, 0.025}= 2.009575\approx2.010

Confidence interval : \overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}

16.40\pm (2.010)\dfrac{4}{\sqrt{50}}\\\\=16.40\pm1.13702770415\\\\=16.40\pm1.1370\\\\=(16.40-1.1370,\ 16.40+1.1370)\\\\=(15.263,\ 17.537)

Required 95% confidence interval :  (15.263,\ 17.537)

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