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damaskus [11]
2 years ago
6

Nathan needs to order some new supplies for the restaurant where he works. The restaurant needs at least 571 forks. There are cu

rrently 361 forks. If each set on sale contains 10 forks, use the drop-down menu below to write an inequality representing
s

s, the number of sets of forks Nathan should buy.
Mathematics
1 answer:
Step2247 [10]2 years ago
3 0

Answer:

The inequality representing  s, the number of sets of forks Nathan should buy is

s ≥ 21

Step-by-step explanation:

From the question, the restaurant needs at least 571 forks, i.e., if n represents the number of forks the restaurant needs, then

n ≥ 571

Also from the question, there are currently 361 forks. If y represents the number of forks the restaurant needs to buy, then

y ≥ 571 - 361

y ≥ 210

Also, each set on sale contains 10 forks. if s represents the number of sets of forks Nathan should buy, then

s ≥ 210/10

s ≥ 21

Hence, the inequality representing  s, the number of sets of forks Nathan should buy is

s ≥ 21

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Answer:

f(x) = k(x - \frac{3}{2})

Step-by-step explanation:

Line q will be graphed on the same grid. The only solution to the system of linear equations formed by lines n and q occurs when x = \frac{3}{2} and y = 0.

Now, as x = \frac{3}{2}  is a solution of the equation, y = f(x) = 0, so, (x - \frac{3}{2}) will be a factor of the linear function y = f(x).

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2 years ago
Transversal EF cuts parallel lines AB and CD as shown in the diagram and m4=55.1 what are m5 and m7? . A. m<5=34.9 and m7=145
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2 years ago
4/9 divided by what equals 12?<br> :)
liraira [26]

Answer:

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The weight of corn chips dispensed into a 14-ounce bag by the dispensing machine has been identified as possessing a normal dist
mamaluj [8]
The probability that a normally distributed dataset with a mean, μ, and statndard deviation, σ, exceeds a value x, is given by

P(X\ \textgreater \ x)=1-P(X\ \textless \ x)=1-P\left(z\ \textless \  \frac{x-\mu}{\frac{\sigma}{\sqrt{n}}} \right)

Given that t<span>he weight of corn chips dispensed into a 14-ounce bag by the dispensing machine is a normal distribution with a mean of 14.5 ounces and a standard deviation of 0.2 ounce.

</span>If <span>100 bags of chips are randomly selected the probability that the mean weight of these 100 bags exceeds 14.6 ounces is given by

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Therefore, the probability that </span><span>the mean weight of these 100 bags exceeds 14.6 ounces is</span> 0.

7 0
2 years ago
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