Answer:
67 eghan says the difference between the least amount of time it takes a student to say the alphabet and the greatest amount
Step-by-step explanation:
Answer:
The answer is explained below
Step-by-step explanation:
STEP 1
Out of 1500 units produced by a company 1,477 are found to be free of a particular type of defect. One needs to rate the performance based on Six Sigma Theory.
STEP 2
Manager can define the performance of a product using defects per million units DPMO metric
DPMO can be find by using
DPMO = Total number of defects in a sample/ No. of opportunities of per error per unit x No. of units * 1,000,000
= 1500 - 1477/ 1 x 1500* 1,000,000
= 23/1500
= 15,333,33
The defect rate of the process can be find by
Defect rate = No. of defects/ No. of units * 100
= 1500 - 1477/1500 * 100
= 23/1500 * 100
= 1.53%
Six Sigma theory focuses on achieving 3.4 defects per million for a certain period of time. However in this, performance of the process is not as good as stated by the manager.

notice the picture of the graph added here
low and behold, x = -17, y is 0, and x= 15, y is 0
the graph is touching the x-axis, an x-intercept
or so-called, a "solution"
Two figures are similar if one is the scaled version of the other.
This is always the case for circles, because their geometry is fixed, and you can't modify it in anyway, otherwise it wouldn't be a circle anymore.
To be more precise, you only need two steps to prove that every two circles are similar:
- Translate one of the two circles so that they have the same center
- Scale the inner circle (for example) unit it has the same radius of the outer one. You can obviously shrink the outer one as well
Now the two circles have the same center and the same radius, and thus they are the same. We just proved that any two circles can be reduced to be the same circle using only translations and scaling, which generate similar shapes.
Recapping, we have:
- Start with circle X and radius r
- Translate it so that it has the same center as circle Y. This new circle, say X', is similar to the first one, because you only translated it.
- Scale the radius of circle X' until it becomes
. This new circle, say X'', is similar to X' because you only scaled it
So, we passed from X to X' to X'', and they are all similar to each other, and in the end we have X''=Y, which ends the proof.