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sertanlavr [38]
2 years ago
14

1. If a basketball player makes 9 baskets in 12 tries, what is her ratio of baskets to tries, in lowest terms?

Mathematics
1 answer:
coldgirl [10]2 years ago
6 0

Answer:

1. 3:4

Step-by-step explanation:

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John deposited $2860 in a bank that pays 9% interest, compounded monthly. Find the amount he will have at the end of 3 years.
kati45 [8]
Please see figure for the answer.

3 0
2 years ago
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Mr Davis is creating a spice mixture for a recipe.2/5 of the spice mixture was oregano 1/3 of the spice mixture was basil the re
attashe74 [19]

Answer: \frac{11}{15}

Step-by-step explanation:

You know that:

- 2/5 of the spice mixture was oregano.

- 1/3 of the spice mixture was basil.

Then, to find the fraction of the total amount of spice mixture that was oregano and basil, you must add both fractions, as following:

- Find the least common multiply of the denominators:

LCM=5*3=15

- Divide the LCM by each original denominator and multiply the result by each numerator.

- Make the addition.

Then, the result is:

\frac{(2*3)+(1*5)}{15}=\frac{6+5}{15}=\frac{11}{15}

7 0
2 years ago
The product of 18 and a number is 109.8
timama [110]

Answer:

6.1!

Step-by-step explanation:

The product means you multiply, so you should divide 109.8 by 18.  That will get you 6.1 as the answer.

8 0
2 years ago
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Thomas wants to invite Madeline to a party. He has an 80% chance of bumping into her at school. Otherwise, he’ll call her on the
Ivenika [448]

Answer:

84%

Step-by-step explanation:

The probability of Thomas bumping into her at school is 80%, so the probability of not bumping into her is 100% - 80% = 20%.

If he doesn't bump into her (20% chance), he will call her, and the probability of asking her in this case is 60%, so the final probability of asking her in this case is:

P_1 = 20\% * 60\% = 12\%

If he bumps into her (80% chance), the probability of asking her is 90%, so the final probability of asking her in this case is:

P_2 = 80\% * 90\% = 72\%

To find the probability of Thomas inviting Madeline to the party, we just have to sum the probabilities we found above:

P = P_1 + P_2

P = 12\% + 72\% = 84\%

5 0
2 years ago
Prove that (sec 12A-1)/(sec 6A-1)=tan 12A/tan 3A
adelina 88 [10]

Let x=3A. Recall the following identities,

\cos^2\theta=\dfrac{1+\cos2\theta}2

\sin^2\theta=\dfrac{1-\cos2\theta}2

\sin2\theta=2\sin\theta\cos\theta

Now,

\dfrac{\sec12A-1}{\sec6A-1}=\dfrac{\sec4x-1}{\sec2x-1}

=\dfrac{\cos2x(1-\cos4x)}{\cos4x(1-\cos2x)}

=\dfrac{2\cos2x\sin^22x}{\cos4x(1-\cos2x)}

=\dfrac{2\cos2x\sin^22x(1+\cos2x)}{\cos4x(1-\cos^22x)}=\dfrac{2\cos2x\sin^22x(1+\cos2x)}{\cos4x\sin^22x}=\dfrac{2\cos2x(1+\cos2x)}{\cos4x}

=\dfrac{4\cos2x\cos^2x}{\cos4x}

=\dfrac{4\cos2x\cos^2x\sin4x}{\cos4x\sin4x}=\dfrac{4\cos2x\cos^2x\tan4x}{\sin4x}

=\dfrac{4\cos2x\cos^2x\tan4x}{2\sin2x\cos2x}=\dfrac{2\cos^2x\tan4x}{\sin2x}

=\dfrac{2\cos^2x\tan4x}{2\sin x\cos x}=\dfrac{\cos x\tan4x}{\sin x}

=\dfrac{\tan4x}{\frac{\sin x}{\cos x}}=\dfrac{\tan4x}{\tan x}=\dfrac{\tan12A}{\tan3A}

QED

5 0
2 years ago
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