1) 26 different outcomes are in the sample space.
2) 1 / 26 is the probability that the computer produces the first letter of your first name.
<u>Step-by-step explanation:</u>
<u>1) You have to find out the different outcomes in the sample space :</u>
- A "Sample space" is defined as the set of all the possible outcomes of an event.
- Here, the given event is randomly selecting a letter from the alphabets.
Therefore, the sample space must contain all the possible alphabets that can be chosen randomly.
The sample space is the set of all the 26 alphabets in English language.
⇒ Sample space = {A,B,C,D...........,Y,Z}
⇒ 26 different outcomes.
<u>2) The probability the computer produces the first letter of your first name :</u>
Here, the required outcome is getting the first letter of your first name.
Probability = No. of required outcomes / total no. of outcomes.
For example, The name Alex Davis has the first letter of the fist name as alphabet 'A'.
∴ Probability = 1 / 26
Similarly, for any first name there is going to be any one alphabet from the 26 alphabets, thus the probability to get the first letter will be always 1 / 26.
Sample Response: A kite has two pairs of
congruent adjacent sides and opposite sides that are not congruent.
Jared has already created one pair of congruent adjacent sides. Since he
has used 60 ft of rope, there are 40 ft remaining. This means that he
will need 20 ft of rope for each of the other sides, or half of the
remaining rope, in order to create another pair of congruent adjacent
sides. Since this is a different length than 30 ft, the shape has
opposite sides that are not congruent.
Answer:
C
Step-by-step explanation:
When you move the decimal either to the right or the left, you change the value. To divide any number by 10, move the decimal point one place to the left. For example:
0.7
7
70
700
7,000
So, for any decimal, when you move the decimal point one place to the right, you multiply that number by 10.
The
formula
, where r! is 1*2*3*...r
is the
formula which gives us the total number of ways of forming groups of r objects out of n objects.
for
example, given 10 objects, there are C(10,6) ways of forming groups of 6, out
of the 10 objects.
<span>Thus, there are C(6, 3) many ways of forming different triples out of 6.</span>

Answer: A.20