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Archy [21]
1 year ago
6

Complexes containing metals with d10 electron configurations are typically colorless because ________. Complexes containing meta

ls with d10 electron configurations are typically colorless because ________. d electrons must be emitted by the complex in order for it to appear colored there are no d electrons to form bonds to ligands a complex must be charged to be colored there is no d electron that can be promoted via the absorption of visible light the empty d orbitals absorb all of the visible wavelengths
Chemistry
1 answer:
algol [13]1 year ago
8 0

Answer:

there is no d electron that can be promoted via the absorption of visible light

Explanation:

One of the properties of transition elements is the possession of incompletely filled d orbitals. This property accounts for their unique colours.

The colours of transition metal compounds stem from d-d transition of electrons due to the presence of vacant d orbitals of appropriate energy to which electrons could be promoted.

For elements whose atoms have a d10 configuration, such vacant orbitals does not exist hence their compounds are not colored.

Sometimes, the colour of transition metal compounds stem from ligand to metal charge transfer(LMCT) for instance in KMnO4.

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URGENT!! 50 Points Please Help!! Will mark brainliest!! Assignment due in 30 minutes.
dedylja [7]

a) The least number of decimal points is 0 so you should round the answer to 43.

b) The least number of significant figures is 2 so round to 7.3

c)The least number of decimal places is 1 so round to 225.7

d) The least number of significant figures is 3 so round to 92.0

e) The least number of significant figures is 3 so round to 32.4

f) The least number of decimal places is 0 so round to 104m^3

Basically, for addition and subtraction round to the least number of decimal places found in the factors, and for multiplication and division round to the least number of significant figures found in the factors.

4 0
2 years ago
A mixture containing KClO3,K2CO3,KHCO3, and KCl was heated, producing CO2,O2, and H2O gases according to the following equations
Nikitich [7]

<u>Answer:</u>

<u>For 1:</u> The mass of KClO_3 in the original mixture is 10.46 g

<u>For 2:</u> The mass of KHCO_3 in the original mixture is 21.11 g

<u>Explanation:</u>

We are given:

Mass of water = 1.90 g

Mass of carbon dioxide = 13.64 g

Mass of oxygen = 4.10 g

  • <u>For 1:</u>

The given chemical reaction for decomposition of KClO_3 follows:

2KClO_3\rightarrow 2KCl+3O_2

By Stoichiometry of the reaction:

(3\times 32)=96g of oxygen is produced when (2\times 122.5)=245g of potassium chlorate is decomposed.

So, 4.10 g of oxygen will be produced when = \frac{245}{96}\times 4.10=10.46g of potassium chlorate is decomposed.

Amount of KClO_3 in the mixture = 10.46 g

  • <u>For 2:</u>

The given chemical reaction for decomposition of KHCO_3 follows:

2KHCO_3\rightarrow K_2O+H_2O+2CO_2

By Stoichiometry of the reaction:

18 g of water is produced when (2\times 100)=200g of potassium bicarbonate is decomposed.

So, 1.90 g of water will be produced when = \frac{200}{18}\times 1.90=21.11g of potassium bicarbonate is decomposed.

Amount of KHCO_3 in the mixture = 21.11 g

4 0
2 years ago
What mass of carbon dioxide gas occupies a volume of 81.3L at 204 kPa and a temperature of 95.0°C?
alexandr1967 [171]

Answer:

236.9g

Explanation:

Given parameters:

Volume of gas  = 81.3L

Pressure of gas = 204kPa

temperature of gas = 95°C

Unknown:

Mass of carbondioxide gas = ?

Solution:

To solve this problem, the ideal gas law will be well suited. The ideal gas law is a fusion of Boyle's law, Charles's law and Avogadro's law.

Mathematically, it is expressed as;

                    PV = nRT

the unknown here is n which is the number of moles;

P is the pressure, V is the volume, R is the gas constant and T is the temperature.

convert pressure into atm

               101.325KPa  = 1atm

             204 kPa = \frac{204}{101.325}   = 2atm

Convert temperature to Kelvin;   95 + 273  = 368K

       2 x 81.3 = n x 0.082 x 368

             n = \frac{2 x 81.3}{0.082 x 368}   = 5.38moles

Since the unknown is mass;

 Mass  = number of moles x molar mass

      Molar mass of carbon dioxide  = 12 + 2(16)  = 44g/mol

 Mass  = 5.38 x 44  = 236.9g

5 0
2 years ago
Chlorine oxide (ClO), which plays an important role in the depletion of ozone, decays rapidly according to the equation 2ClO(g)
Sphinxa [80]

Answer:

It is a zero order reaction and k=0.005M/s

Explanation:

Once you plot the graph, you can see it is a linear equation which decays. This is common to zero order reaction which are given by the following equation: C=Co-kt. The equation given by the graph is C=1x10-5 - 0.0015t. Therefore, the slope = -K

Download pdf
3 0
2 years ago
!!15 points!!Which of the following phrases describes how the position of an electron
ki77a [65]

Answer:

A. The farther an electron is from the nucleus, the greater its energy.

Explanation:

8 0
2 years ago
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