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marissa [1.9K]
2 years ago
14

Element X is a radioactive isotope such that every 82 years, its mass decreases by half. Given that the initial mass of a sample

of Element X is 8900 grams, how long would it be until the mass of the sample reached 7700 grams, to the nearest tenth of a year
Chemistry
1 answer:
lesantik [10]2 years ago
4 0

Answer: 17 years

Explanation:

Expression for rate law for first order kinetics  for radioactive substance is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{82years}=8.4\times 10^{-3}years^{-1}

b) for 8900 g of the mass of the sample to reach  7700 grams

t=\frac{2.303}{8.4\times 10^{-3}}\log\frac{8900}{7700}

t=17years

Thus it will take 17 years

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a compound contain 8.57g of carbon and 1.43g of hydrogen. The relative formula mass is 70 calculate the empirical formula of the
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Answer:

Empirical formula: CH2

Molecular formula: C5H10

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1 year ago
Two electrons in an atom are separated by 1.5 ✕ 10-10 m, the typical size of an atom. what is the electric force between them?
densk [106]
Given two electrons with charge of 1.5x10^-10 m 

The electostatic force between them is determined by this formula: 

F = kq1q2/r^2
   
where 

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r = 2.82x10^-15

F = 9x10^9 * (1.5x10^-10)^2 / 2.82x10^-15
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2 years ago
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On a clear day at sea level, with a temperature of 25 °C, the partial pressure of N2 in air is 0.78 atm and the concentration of
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Answer : The partial pressure of nitrogen gas is, 2.94 atm

Explanation:

According top the Henry's Law, the concentration of a gas in a liquid is directly proportional to the partial pressure of the gas.

C\propto P

C=K_H\times P

K_H is Henry's constant.

or,

\frac{C_1}{C_2}=\frac{P_1}{P_2}

where,

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C_2 = final concentration of gas = 2.0\times 10^{-3}M

P_1 = initial partial pressure of gas = 0.78 atm

P_2 = final partial pressure of gas = ?

Now put all the given values in the above formula, we get the final partial pressure of the gas.

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P_2=2.94atm

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5 0
2 years ago
Using the equation, C5H12 + 8O2 Imported Asset 5CO2 + 6H2O, if an excess of pentane (C5H12) were supplied, but only 4 moles of o
ser-zykov [4K]
Answer: 3 <span>moles of water would be produced in present case.
</span>
Reason:
Reaction involved in present case is:
<span>                            C5H12 + 8O2 </span>→<span> 5CO2 + 6H2O

In above reaction, 1 mole of C5H12 reacts with 8 moles of oxygen to give 6 moles of water.

Thus, 4 moles of oxygen will react with 0.5 mole of C5H12, to generate 3 moles of H2O.</span>
7 0
2 years ago
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A hypothetical substance has a melting point of −10°C and a boiling point of 155°C. If this substance is heated from 2°C to the
igor_vitrenko [27]

Answer:

The specific heat capacity of liquid and the het of vaporization is used.

.

Explanation:

Step 1: Data given

A substance at temperature 2°C.

The substance has a melting point of −10°C and a boiling point of 155°C.

The initial temperature is 2°C which is between the melting point (-10°C) and the boiling point (155°C). At 2°C, the substance is liquid.

At 155°C, the substance changes from liquid to gas.

To calculate the heat gained for the change of 2°C liquid to 155°C liquid, specific heat capacity of the liquid (C) is needed.

To calculate the heat gained for the change of liquid to 155°C gas, heat of vaporization (D) is needed.

The <u>specific heat of the solid is not used</u> because the substance is changed from liquid to gas. it doesn't come in the state of solid.

<u>Heat of fusion is not used</u>, because it's used when there is a change from its state from a solid to a liquid,

<u>The specific heat capacity of the gas is not used</u>, because the substance only formes gas after reaching 155 °C

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