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zhuklara [117]
2 years ago
13

If your sample contained a volatile impurity, what value would be in error

Chemistry
1 answer:
weeeeeb [17]2 years ago
6 0
A volatile impurity, is an impurity that evaporates quickly, so, if you were to conduct an experiment on a substance with this type of impurity, the evaporation point, and the mass of the substance at high temperatures would be in error. 
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2. After quenching your solution with ice, the resulting aqueous layer became acidic. Use a chemical equation to explain how the
alexandr402 [8]

Answer:

C2H5Cl + H20 ⇆ C2OOH4

Explanation:

The left over acetyl chloride which reacted with water to produce acetic acid

3 0
2 years ago
Write a balanced half-reaction describing the reduction of aqueous chromium(IV) cations to solid chromium.
Aliun [14]

The balanced half-reaction: Cr⁴⁺(aq)+ 4e⁻ → Cr(s).

<span> Chromium(IV) cations gain four electrons and became solid chromium with neutral charge.
</span>Reduction is lowering oxidation number because element or ions gain electrons. 

Oxidation reaction is increasing of oxidation number of element, because element or ion lost electrons in chemical reaction.

<span>
</span>

3 0
2 years ago
Iron-59 is used in medicine to diagnose blood circulation disorders. The half life of iron-59 is 44.5 days. How much of a 2.000
kolezko [41]

Answer:

0.258 mg of iron remains.

Explanation:

To solve this problem we can use the formula

M₂ = M₀ * 0.5^{\frac{t}{44.5} }

Where M₂ is the mass remaining, M₀ is the initial mass, and t is time in days.

Using the data given by the problem:

M₂ = 2.000 mg * 0.5^{\frac{133.5}{44.5} }

M₂ = 0.258 mg

7 0
2 years ago
If you weigh 100 kg, how much would you weigh if all the water were removed from your body? A65 kg B45 kg C50 kg D35 kg
Mekhanik [1.2K]

Answer:

B. 45k

The human body is about 60 to 70% water.

(:

5 0
2 years ago
A poisoned pill contains 0.00048 moles of KCN. How many molecules are in this sample?
mario62 [17]

Answer:

2.89 \times  {10}^{20}  \:  \: molecules

Explanation:

The number of molecules of KCN can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.00048 × 6.02 × 10²³

We have the final answer as

2.89 \times  {10}^{20}  \:  \:  \: molecules

Hope this helps you

7 0
1 year ago
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