I think that you typed wrongly. That has to be f(x)= -2x+8
If f(x)= -2x+8, we can solve that problem.
We replace x= -1.8 in that expression, that means: f(-1.8)= -2x(-1.8)+8= 3.6+8=11.6
But if the formula of f(x)=-2+8, that means f(x) has a stable value and that value is -2+8=6.
So for all x we always have f(x)=f(-1.8)=6
<span>It would be...
C) true, because the standard deviation describes how far, on average, each observation is from the typical value. a larger standard deviation means that observations are more distant from the typical value, and therefore, more dispersed.
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Answer:
The parametric equations for the tangent line are
:
x = Cos(10) - t×Sin(10)
y = Sin(10) + t×Cos(10)
z = 20 + 2t
Step-by-step explanation:
When Z=20:
Z=2t=20 ⇒ t=10
The point of tangency is:
r(10)= Cos(10) i + Sin(10) j + 20 k
We have to find the derivative of r(t) to get the tangent line:
r'(t)= -Sin(t) i + Cos(t) j + 2 k
The direction vector at t=10 is:
r'(10)= -Sin(10) i + Cos(10) j + 2 k
So, the equation of the tangent line is given by:
x = cos 10 -t×Sin(10)
y = sin 10 + t×Cos(10)
z = 20 + 2t
