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ehidna [41]
2 years ago
14

I need help Type th temperature (in Kelvin) in the left column and the volumes in the right column, being sure to keep pairs of

data together. then click resize window to fit data.
the data appears to be
linear
quadratic
exponential
logarithmic​

Chemistry
2 answers:
e-lub [12.9K]2 years ago
7 0

Answer:

sorry nahi pata tha muje

bija089 [108]2 years ago
5 0

Answer:

Linear

Explanation:

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A pound is approximately 0.45 kilogram. A person weighs 87 kilograms. What is the person’s weight, in pounds, when expressed to
Sauron [17]

Answer:

87 kilograms =191.8 pounds

4 0
2 years ago
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The compound AX2 decomposes according to the equation, 2 AX2(g) => 2 AX(g) + X2(g). In one experiment, AX2 was measured at va
Karolina [17]

Answer:

0.0011 mol/L.s

Explanation:

The average rate of disappearing of the reagent is the variation of the concentration of it divided by the time that this variation is being measured. The reaction rate, is proportional to the coefficient of the substance, so, for a generic reaction:

aA + bB --> cC + dD

rate = -(1/a)Δ[A]/Δt = -(1/b)Δ[B]/Δt = (1/c)Δ[C]/Δdt = (1/d)Δ[D]/dt

The minus sign is because of the reagent is desapering, so:

rate = -(1/2)*(0.0209 - 0.0300)/(10 - 6)

rate = 0.0011 mol/L.s

8 0
2 years ago
A graduated cylinder initially has 32.5 mL of water in it. After a 75.0 g piece of lead (Pb) is added to the graduated cylinder,
Mice21 [21]

Answer:

39.1-32.5 and you will find your answer it always like that, you subtract your starting point from your ending point

Explanation:

6 0
2 years ago
The equation below shows the products formed when a solution of silver nitrate (AgNO3) reacts with a solution of sodium chloride
d1i1m1o1n [39]
I would say that the answer has to be C
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3 0
2 years ago
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How many moles of alanine, C3H7NO2, are there in 159 g of alanine?How many moles of alanine, C3H7NO2, are there in 159 g of alan
Vanyuwa [196]

To find the number of moles of Alanine, we first need to find its molar mass

<u>Finding the Molar mass:</u>

To our convenience, we are already given the chemical formula of Alanine

Chemical formula:  C₃H₇NO₂

Now, we will use this formula to find the molar mass of Alanine

to do that, we will replace the chemical symbols of elements with their respective molar masses and add them together

<em>We know the following molar masses:</em>

<em>C is 12 g/mol</em>

<em>H is 1 g/mol</em>

<em>N is 14 g/mol</em>

<em>O is 16 g/mol</em>

Now, we will replace the chemical symbols with their molar mass and will be multiplied by their values in subscript

C₃H₇NO₂

Molar mass = (12)*3  + (1)*7 + (14)*1 + (16)*2

Molar mass = 36 + 7 + 14 + 32

Molar mass = 89 grams/mol

<u>Number of moles of Alanine in a 159 gram sample:</u>

Number of moles = Given mass / Molar mass

Number of moles = 159 / 89

Number of Moles = 1.78 moles

5 0
2 years ago
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