Greg builds a new pond which has a volume of 7.35 m3. It is 4.2 m long and 50 cm deep. What is the width of the pond? m There wi
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Answer:
a) P-value = 0.0968
b) P-value = 0.2207
c) P-value = 0.0239
d) P-value = 0.0040
e) P-value = 0.5636
Step-by-step explanation:
As the hypothesis are defined with a ">" sign, instead of an "≠", the test is right-tailed.
For this type of test, the P-value is defined as:
being z* the value for each test statistic.
The probability P is calculated from the standard normal distribution.
Then, we can calculate for each case:
(a) 1.30
(b) 0.77
(c) 1.98
(d) 2.65
(e) −0.16
Answer:
(a) The probability of exactly three flaws in 150 m of cable is 0.21246
(b) The probability of at least two flaws in 100m of cable is 0.69155
(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063
Step-by-step explanation:
A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by
for x = 0, 1, 2, ...
where , the mean number of successes.
(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is
The probability of exactly three flaws in 150 m of cable is
(b) The probability of at least two flaws in 100m of cable is,
we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is
(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is
The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is
Let's say x is J because it's Lemon Juice.
It's said that the pH of J is less than 4 so: pH(J) < 4 and pH(J) is greater than 1.5 so: pH(J) > 1.5
Now we can construct:
Or simply:
We can also write this with an interval:
Hope this helps.
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