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vitfil [10]
2 years ago
11

Greg builds a new pond which has a volume of 7.35 m3. It is 4.2 m long and 50 cm deep. What is the width of the pond? m There wi

ll be a circular patio with a diameter of 7 metres. Greg is going to put a tiled edge around the patio. What is the circumference of the patio? m Circumference of a circle = 2πr Use π = 3.14
Mathematics
1 answer:
solmaris [256]2 years ago
8 0
Assuming the pond is rectangular in shape, therefore Volume = Width * Length * Depth
Width = Volume/(Length*Depth)
Width = 7.35/4.2*0.5 = 7.35/2.1 = 3.5 m

r= diameter / 2 = 7/2 = 3.5m
Circumference of the patio = 2*3.14*3.5= 21.98m
You might be interested in
A factory produces 125 bags of jelly beans every 10 seconds. Is there a linear function proportional? How do you know?
babunello [35]
This problem is proportional! for every 1 second 12.5 jellybeans are made!
3 0
1 year ago
Si un conductor llena su tanque con $600 y recorre 250 kilómetros, ¿Cuántos kilómetros podrá recorrer con $350 de combustible? (
LekaFEV [45]

Answer:

145.83 kilómetros.

Step-by-step explanation:

Si un conductor llena su tanque con $600 y recorre 250 kilómetros, para determinar cuántos kilómetros podrá recorrer con $350 de combustible se debe realizar el siguiente cálculo:

600 = 250

350 = X

350 x 250 / 600 = X

87,500 / 600 = X

145.83 = X

Así, con $350 de combustible se podrán recorrer 145.83 kilómetros.

4 0
2 years ago
PROBLEM SOLVING Scientists conducted aerial surveys of a seal sanctuary and recorded the number x of seals they observed during
Akimi4 [234]

Answer:

Probability that at most 50 seals were observed during a randomly chosen survey is 0.0516.

Step-by-step explanation:

We are given that Scientists conducted aerial surveys of a seal sanctuary and recorded the number x of seals they observed during each  survey.

The numbers of seals observed were normally distributed with a mean of 73 seals and a standard deviation of 14.1 seals.

Let X = <u><em>numbers of seals observed</em></u>

The z score probability distribution for normal distribution is given by;

                             Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean numbers of seals = 73

            \sigma = standard deviation = 14.1

Now, the probability that at most 50 seals were observed during a randomly chosen survey is given by = P(X \leq 50 seals)

            P(X \leq 50) = P( \frac{X-\mu}{\sigma} \leq \frac{50-73}{14.1} ) = P(Z \leq -1.63) = 1 - P(Z < 1.63)    

                                                          = 1 - 0.94845 = <u>0.0516</u>

The above probability is calculated by looking at the value of x = 1.63 in the z table which has an area of 0.94845.

4 0
2 years ago
If SYSTEM is coded as '131625', and KARMA is coded as '94854' then MARKET is coded as _____? (A) 845926 (B) 548926 (C) 629845 (D
MArishka [77]

Answer:

B. 548926

Step-by-step explanation:

Given

SYSTEM => '131625', and KARMA => '94854'

Required

MARKET is coded as?

To solve this, we simply map out each letter to the given characters;

This is done as follows:

S-> 1

Y-> 3

S-> 1

T-> 6

E -> 2

M-> 5

K-> 9

A-> 4

R-> 8

M-> 5

A -> 4

Remove repetitions

S-> 1

Y-> 3

T-> 6

E -> 2

M-> 5

K-> 9

R-> 8

A -> 4

Now, we can code MARKET using the same system

M-> 5

A -> 4

R-> 8

K-> 9

E -> 2

T-> 6

MARKET => 548926

5 0
2 years ago
Anna wants to take fitness classes. She compares two gyms to determine which would be the best deal for her. Fit Fast charges a
steposvetlana [31]
This is sort of weird to write without any numbers, but it's not too hard. take your info out of the word problem:

fit fast = fee per class
stepping up = fee per class + monthly fee

now you just change all of that into variables, essentially:

F = cx
S = cx + m

so, fit fast is the cost of classes (c) times the number of classes taken (x). stepping up is the cost of classes times x, PLUS that additional monthly fee (m).
7 0
2 years ago
Read 2 more answers
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