So if 32 oz is 20% more than the average bottle, you multiply 32 by .20 which gives you 6.4. This means that the 32 oz bottle is 6.4 oz more than the regular bottle. Furthermore, 32 - 6.4 = 25.6 so that's how big the typical bottle is.
Answer:
h=7.65
Step-by-step explanation:
H is directly proportional to the square root of p;
Let k be the constant of proportionality;
Means h=k√p
This means for corresponding points of h and p such that (h1,p1) and (h2,p2) we have;
h1/√p1=h2/√p2
Let h= 5.4 when p = 1.44 and h when p =2.89 be respectively (h1,p1) and (h2,p2)
So that
5.4/√1.44=h/√2.89
5.4/√1.44 ×√2.89 = h
7.65= h
h=7.65
To graph it, just graph

and

and see where they intersect
I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it
hmm
multiply both sides by -1

multiply both sides by



minus 1 from both sides and minus 6(3^x) from both sides

use u subsitution

we can rewrite it as

now factor
I mean use quadratic formula
for

so for 0=u^2-16u-1, a=1, b=-16, c=-1


remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor


if you take the log base 3 of both sides you get

if you use ln then

then
You do the implcit differentation, then solve for y' and check where this is defined.
In your case: Differentiate implicitly: 2xy + x²y' - y² - x*2yy' = 0
Solve for y': y'(x²-2xy) +2xy - y² = 0
y' = (2xy-y²) / (x²-2xy)
Check where defined: y' is not defined if the denominator becomes zero, i.e.
x² - 2xy = 0 x(x - 2y) = 0
This has formal solutions x=0 and y=x/2. Now we check whether these values are possible for the initially given definition of y:
0^2*y - 0*y^2 =? 4 0 =? 4
This is impossible, hence the function is not defined for 0, and we can disregard this.
x^2*(x/2) - x(x/2)^2 =? 4 x^3/2 - x^3/4 = 4 x^3/4 = 4 x^3=16 x^3 = 16 x = cubicroot(16)
This is a possible value for y, so we have a point where y is defined, but not y'.
The solution to all of it is hence D - { cubicroot(16) }, where D is the domain of y (which nobody has asked for in this example :-).
(Actually, the check whether 0 is in D is superfluous: If you write as solution D - { 0, cubicroot(16) }, this is also correct - only it so happens that 0 is not in D, so the set difference cannot take it out of there ...).
If someone asks for that D, you have to solve the definition for y and find that domain - I don't know of any [general] way to find the domain without solving for the explicit function).