Answer:
Step-by-step explanation:
Fraction of the total that is for corn (TC - Total corn):
fraction of the corn section that is for white corn (WC - white corn in the corn seccion):
we need to find the fraction of the whole field that is for the white corn.
For this we need to find how much is 
out of the 
destinated to corn, and this will be the fraction of the total that is for white corn. We find this fraction by multiplying the fraction of corn () by the fraction of white corn in the corn section ().
I will call the total fraction of white corn TWC, thus:
the answer is: of the whole field is planted with white corn
The shape of the graph is similar to the letter W; however, the region of interest will lie on the right of the origin, which means only the right half of the W(a negative number of cans cannot be produced). The profit produced will be maximized if the number of cans produced is greater than 3. The company will be at a loss if the number of cans produced is near 2.5. The break even situations are present if the company produces 2 or 3 cans.
<span>(x – 8)² + (y – 9)² = 3
(x – 8)² + (y – 9)² = 14
</span>are the correct answers
Answer:
$163.54
Step-by-step explanation:
Volume of rectangular container = 10m^3
Length = 2(width)
Material for the base cost $10 per square meter
Material for the side cost $6 per square meter
Volume = L*B*H
L= 2W
V = (2W).W. H
10 = 2W^2.H
H = 10 /2W^2
H = 5/W^2
Let C(w) = cost function
C(w) = 10(L.W) + 6(2.L.H + 2.W.H)
= 10(2W.W) + 6(2.2W.H + 2.W.H)
= 10(2W^2) + 6(4W.H + 2.W.H)
= 10(2W^2) + 6(4W*5/W^2 + 2.W*5/W^2)
= 20W^2 + 6(20/W + 10/W)
= 20W^2 + 6((10+20)/W)
= 20W^2 + 6(30/W)
C(w) = 20W^2 + 180/W
To find the minimum value, differentiate C with respect to w
C'(w) = 40W - 180/W^2
Put C'(w) = 0
0 = 40W - 180/W^2
40W = 180/W^2
40W^3 = 180
W^3 = 180/40
W^3 = 4.5
W = cube rt(4.5)
W = 1.65m
C = 20(1.65)^2 + 180/1.65
C = 54.45 + 109.09
C= $163.54
Minimum cost = $163.54
Answer:
Step-by-step explanation:
Given that we assume no direct factory overhead costs (i.e., inventory carry costs) and $3 million dollars in combined promotion and sales budget, the Deal product manager wishes to achieve a product contribution margin of 35%.
Sales - variable cost = Fixed cost + profit
Here fixed cost = 3 million dollars
Sales - variable = contribution = 35%
35% should atleast meet the fixed cost
i.e. 35% = 3 million
100% = 8.57 million can be cost
Since fixed cost will not change and remain 3 million these 5,57 million can be given to material and labor costs
So material and labor cost should be limited upto 5.57 million increase.
